One car leaves a given point and travels cast at 20mph. Another car leaves I hour later and travels north at 35 mph. At what rate is the distance between the cars changing at the instant the second car has been travelling for 3 hours? (source : faculty mell h
One car leaves a given point and travels cast at 20mph. Another car leaves I hour later and travels north at 35 mph. At what rate is the distance between the cars changing at the instant the second car has been travelling for 3 hours? (source : faculty mell h
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![One car leaves a given point and travels cast at 20mph. Another car leaves I hour later and travels_north
at 35 mph. At what rate is the distance between the cars changing at the instant the second car has been
travelling for 3 hours? (source faculty. math. illinois.edu)
solution:
d=rt
4
Z
X-
dy
dt
x² + y² = 2²
x(t) = 20t
= 35 y(t) = 35 (t-1)
36
व
dz
dt = ?
= 20
px dy + by
dz
27/2 = 2 2 1/²7/2
ky वर 47 वर
60 (20) + 70 (35) = 10√75
dz
dt
3650 = 10 √85 det
13√√58
17
dz
dt
≈ 39.59
x² + y² = 2²
X 60
y = 70
Choices
√60²470² = 2²
√√3600+4900 = 2²
√8500 = z²
2 = 10 √ 85
a) 29.50
b) 34.78
c) 35.90
d) 39.59 ✓](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ea9ad8a-b3e5-4e00-ada7-546c74e1bc34%2F2fc57212-4131-4de9-bd22-de6a3fa02023%2Fm6bli0lm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:One car leaves a given point and travels cast at 20mph. Another car leaves I hour later and travels_north
at 35 mph. At what rate is the distance between the cars changing at the instant the second car has been
travelling for 3 hours? (source faculty. math. illinois.edu)
solution:
d=rt
4
Z
X-
dy
dt
x² + y² = 2²
x(t) = 20t
= 35 y(t) = 35 (t-1)
36
व
dz
dt = ?
= 20
px dy + by
dz
27/2 = 2 2 1/²7/2
ky वर 47 वर
60 (20) + 70 (35) = 10√75
dz
dt
3650 = 10 √85 det
13√√58
17
dz
dt
≈ 39.59
x² + y² = 2²
X 60
y = 70
Choices
√60²470² = 2²
√√3600+4900 = 2²
√8500 = z²
2 = 10 √ 85
a) 29.50
b) 34.78
c) 35.90
d) 39.59 ✓
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