can you please help me ??? One can conceive an atomic nucleus, as a sphere charged uniformly,and positively. Let the proton number be Z; the charge in tensity ofei ther electron or proton is e =1.6x1019 Coulomb. Thereby the chargein tensity of the nucleus athand, becomes Ze. Letits radius be R.a) Consider a location denoted by the dis tance r to the center of thenucleus, such thatr>R, and write atr (in MKS unit system), theelectric field intensity E(r) and the electric poten tial V(r) created bythe nucleus.b) Write the rela tionship between these two quantiti tes, and the reasonfor it c) In Rutherford experiment, helium nuclei also known as alpha particles,which consist of two protons and two neutrons were acceleratedthrough an electric potential difference, and then directed towards avery thin Gold foil. Although most of these charged particles passed123through the foil, almost unaffectedly, some were observed to bedeflected sharply, almost backwards. Rutherford (1909 -1911) wasthereby led to the conclusion that Gold atoms consist mostly of void,buthave strongly and positively charged central regions, namely nuclei.In such an experiment assume that an alpha particle with a positivecharge 2e is accelerated through a potential difference of AV and thenhappens to strike, head on, a Gold nucleus of positive charge Ze. Theenergy W it would then acquire would be (by definition of electricpotential) W=2EAV. The distance of closest approach d, in such aspecial collision is expected to give an approximate value for theradius of gold nucleus. First, show that the alpha electric potentialenergy W, atd (in MKS unit system), becomes2ze?W =4rtg d,and thereby, one can write for the closest dis tance dZed =4πε Δνd) Calculate d, in the lightof the following data, in terms of the radius Rof the Gold nucleus, which had been afterwards measured.= 9x 10° N m² /C²|4rte,(MKS), AV= 6 x 106 Volt, Z=79, R=8x1015 m.e) Given thatalpha's mass is m = 6.6 x 1027 kg, find its velocity inmeters/ second.

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One can conceive an atomic nucleus, as a sphere charged uniformly, and positively. Let the proton number be Z; the charge in tensity of ei ther electron or proton is e =1.6x1019Coulomb. Thereby the charge intensity of the nucleus athand, becomes Ze. Letits radius be R. a) Consider a location denoted by the dis tance r to the cen ter of the nucleus, such thatr>R, and wri te atr (in MKS unit system), the electric field intensity E(r) and the electric poten tial V(r) created by the nucleus.