Once I went skiing. I was at the bottom of a snow ramp with a speed of 14.0 m/s. Assuming that the coefficient of friction between the snow and the skis was 0.2 determine my speed at the top of the ramp. The angle theta with the horizontal was 25°. The rise of the snow ramp was h=3.5 meters high. h Skier
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- A skier starts from rest at the top of a hill that is inclined at 10.0° with respect to the horizontal. The hillside is 190 m long, and the coefficient of friction between snow and skis is 0.0750. At the bottom of the hill, the snow is level and the coefficient of friction is unchanged. How far does the skier glide along the horizontal portion of the snow before coming to rest? mThe following information pertains to questions 1, 2, and 3. A workman pulls a sled across an asphalt road using a rope at angle 0 above the horizontal direction. The workman pulls with 1,000[N] of force. The coefficients of friction of the sled with the road are u=1.00 and µ=0.70. The sled has mass m. The sled is initially at rest. T710Q0[N]. 1) Which expression gives the magnitude of fmax for the situation illustrated above? A) mg B) mg – 1000cos(0) C) - mg + 1000cos(0) D) mg-1000sin(0) E) mg+ 1000sin(0) F) None of the aboveAn empty sled of mass 25 kg slides down a muiddy hill with a constant speed of 2.4 m/s The slope of the hill is inclined at an angle of 15 degrees with the horizontal. a. Calculate the frictional force on the sled as it slides down the slope b.Calculate the coefficient of friction between the sled and the muddy surface of the slope c. The sled reaches the bottom of the slope and continues of horizontal ground. Assume the same coefficient of friction. In terms of velocity and acceleration, describe the motion of the sled as it travels on horizontal ground.
- i need help with this pleaseA student applies a 100 N force at an angle 30° below the horizontal to a block causing the block to move at a constant speed along a level ground. Which statement regarding the kinetic friction on the block is most accurate? 100 N 30 The kinetic friction force is negligible and can be rounded to 0 N. The kinetic friction force is equal to 100 N. The kinetic friction force is greater than 100 N. The kinetic friction force is less than 100 N. O O O Oa frictionless plane is 10.0 m long and inclined at 31.0 degree a sled starts at the bottom with an initial speed of 5.40 m/s up to incline. when the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed v1. both sleds reach the bottom of the cline at the same time. A. determine the distance that the first sled traveled up the incline. ___________ m Determine the initial speed of the second sled _________ m/s
- 4.15A sled and rider have a total mass of 60.0 kg. They are on a snowy hill. The coefficient of kinetic friction between the sled and the snow is 0.150. The angle of the hill's slope measured upward from the horizontal is 24.0°. What is the acceleration of the rider?Is the acceleration greater, less than, or equal to your result if a more massive rider uses the same sled on the same hill? Explain.You want to lift a heavy box with a mass L = 89.0 kg using the two-ideal pulley system as shown. With what minimum force do you have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box. L kg N
- Problem 7: A block of mass m = 59 kg slides along a horizontal surface. The coefficient of friction between the block and the surface is u = 0.29. The block has an initial speed of v, = 18 m/s in the positive x-direction as shown. mYou want to lift a heavy box with a mass L = 91.0 kg using the two-ideal pulley system as shown. With what minimum force do you have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box. Lkg NA box is launched up a rough incline with an initial velocity, vo = 6.3 m/s, as in the figure below. The coefficient of kinetic friction between the box and incline is K = 0.05. The angle in the figure is = 39.8 degrees. What speed will the box have when it returns to its initial position at the bottom? With explanation please. VO 0