Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.1, ß = 1.1, and y = 0.5. [Hint: Th parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, le(x!B)a f(x; a, B): Ba * 20 x < 0 by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.6309 X (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.5704 X (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.399 x days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.)

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the
individual becomes infectious. An article proposes a Weibull distribution with a = 2.1, ß = 1.1, and y = 0.5. [Hint: The two-
parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location
parameter: replace x in the equation below,
f(x; a, B)
=
a
Ba
mean
-¹e-(x/B) a
by x - y and x ≥ 0 by x ≥ y.]
(a) Calculate P(1 < X < 2). (Round your answer to four decimal places.)
0.6309
X
x 20
(b) Calculate P(X> 1.5). (Round your answer to four decimal places.)
0.5704
X
standard deviation
x < 0
(c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.)
2.399
X days
(d) What are the mean and standard deviation of X? (Round your answers to three decimal places.)
X days
X days
0.7458
0.115
Transcribed Image Text:Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.1, ß = 1.1, and y = 0.5. [Hint: The two- parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, f(x; a, B) = a Ba mean -¹e-(x/B) a by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 0.6309 X x 20 (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) 0.5704 X standard deviation x < 0 (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.399 X days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) X days X days 0.7458 0.115
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