Onaway Major (1 = Computer Science, 2 = Engineering and Other Sciences, 3 = Other) hseng: Average high school grade in English Descriptive hseng 95% Confidence Interval for Mean N Мean Std. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum 1 78 8.32 1.428 .162 8.00 8.64 4 10 2 78 8.37 1.831 .207 7.96 8.78 4 10 3 78 8.01 1.499 .170 7.67 8.35 3 10 Total 234 8.24 1.597 .104 8.03 8.44 3 10 Test of Homogeneity of Variances Levene Stati df1 df2 Sig. hseng Based on Mean 1.467 231 .233 Based on Median .653 2 231 .522 Based on Median and with .653 2 202.246 .522 adjusted df Based on trimmed mean 1.244 231 .290 ANOVA hseng Sum of Squares df Mean Square F Sig. Between Groups 5.880 2.940 1.155 .317 Within Groups 588.192 231 2.546 Total 594.073 233 Robust Tests of Equality of Means hseng Statistica df1 df2 Sig. Welch 1.201 2 152.482 .304 Brown-Forsythe 1.155 2 219.716 .317 Q-Based on the above data, A researcher wants to investigate whether there are significant differences in high school grade in English among different majors? test the hypothesis, interpret the result

Onaway Major (1 = Computer Science, 2 = Engineering and Other Sciences, 3 = Other) hseng: Average high school grade in English Descriptive hseng 95% Confidence Interval for Mean N Мean Std. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum 1 78 8.32 1.428 .162 8.00 8.64 4 10 2 78 8.37 1.831 .207 7.96 8.78 4 10 3 78 8.01 1.499 .170 7.67 8.35 3 10 Total 234 8.24 1.597 .104 8.03 8.44 3 10 Test of Homogeneity of Variances Levene Stati df1 df2 Sig. hseng Based on Mean 1.467 231 .233 Based on Median .653 2 231 .522 Based on Median and with .653 2 202.246 .522 adjusted df Based on trimmed mean 1.244 231 .290 ANOVA hseng Sum of Squares df Mean Square F Sig. Between Groups 5.880 2.940 1.155 .317 Within Groups 588.192 231 2.546 Total 594.073 233 Robust Tests of Equality of Means hseng Statistica df1 df2 Sig. Welch 1.201 2 152.482 .304 Brown-Forsythe 1.155 2 219.716 .317 Q-Based on the above data, A researcher wants to investigate whether there are significant differences in high school grade in English among different majors? test the hypothesis, interpret the result

Name: OnawayMajor (1 = Computer Science, 2 = Engineering and Other Sciences
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: OnawayMajor (1 = Computer Science, 2 = Engineering and Other Sciences, 3 = Other)hseng: Average high school grade in EnglishDescriptivehseng95% Confidence Interval forMeanNМeanStd. Deviation Std. Error Lower Bound Upper Bound Minimum Maximum1788.321

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

I need answer within 20 minutes please please with my best wishes
foullu standard deviatiðll UI Find the 99% confidence interval of the differences in IS 4.3. 24 19 23 the ages. 21. Television Watching The average number of hours of television watched per week by women over age 22 8. age 55 watch an average 55 is 48 hours. Men over age 55 watch an average of 43 hours of television per week. Random samples of 40 men and 40 women from a large retirement community yielded the following results. At the 0.01 level of significance, can it be concluded that women watch more television per week than men? Sample size Population standard Mean deviation Women an Men 40 48.2 5.6 th 40 Source: World Almanac 2012. 44.3 4.5
4) Question: A sample of 40 patients shows that their average cholesterol level is 200 mg/dL with a standard deviation of 20 mg/dI.. Construct a 99% confidence interval for the population mean cholesterol level.
library > MAT 240: Applied Statistics home >7.2: Confidence intervals for population proportions E zyBooks catalog 2 Help/FAQ LaShonda Ce CHALLEMCE 721 Confidence intervals for population proportions. ACTIVITY Critical values for quick reference during this activity. Confidence Jevel Critical value 0.90 2* = 1.645 0.95 2* = 1.960 0.99 2* = 2.576 3876741091676 qlany? Jurmp to level 1 In a poll of 1000 randomly selected voters in a local election, 778 voters were against school bond measures. What is the sample proportion p? Ex: 0.123 What is the margin of error m for the 90% confidence level? Ex: 0.123 Check Next Feedback? 8:19 O search 74°F A a O O D d0) 4/24/ PrtSc Insert Delete + F3 F5 F6 F7 F9 F10 F11 F12 F4 %23 24 & Num Lock Backspace 8. 169 T. Y Home 4- F Enter C V B N M Shift Alt Ctrl Home PDn V -
Friendship Motivation Scale for Children (FMSC), a scale de- signed to assess children’s desire for friendships. Two interesting conclusions are that friends generally report similar levels of the FMSC and girls tend to score higher on the FMSC than boys. Boys in the seventh grade scored a mean of 9.32 with a standard deviation of 1.71, and girls in the seventh grade scored a mean of 10.04 with a standard deviation of 1.83. Assuming that FMSC scores are normally distributed, determine the percentage of seventh-grade boys who have FMSC scores within a). one standard deviation to either side of the mean. b). two standard deviations to either side of the mean. c). three standard deviations to either side of the mean. d). Repeat parts (a)–(c) for seventh-grade girls.
I'm struggling with this problem and I need some help with it, please?
A new material will replace the old material only if there is significant evidence that the mean strength of the new material is more than 2 units higher than the mean strength of the old material. Sample from new material: mean is 98.064 , SD is 5.6 and sample size is 13 Sample from old material: mean is 95.282 , SD is 5.8 and sample size is 78 We do not know population standard deviations. Consider the test ?0:????−????=2H0:μnew−μold=2 vs. ?0:????−????>2H0:μnew−μold>2 What is the p-value? (Hint: best to use software, or else the Desmos Calculator for the 2 sample T and Z test) Give as a decimal between 0 and 1 accurate to at least 4 decimal places.
You want to estimate the mean weight of quarters in circulation. A sample of 40 quarters has a mean weight of 5.626 grams and a standard deviation of 0.059 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) an example Get more help - grams. Clear all
Just need help with part 3, thank you!
I would like an explanation of the following three tables
Question Heip v A data set includes 103 body temperatures of healthy adult humans having a mean of 98 3°F and a standard deviation of 0.73°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans What does the sample suggest about the use of 98 6°F as the mean body temperature? Cick here to view at distribution table ckhere to viepage t of the standard normal đistribution table LAe to view. page 2 of the standard normal distribution table What is the confidence interval estimate of the population mean u? (Round to three decimai places as needed) leouran ernthe edfelds and then click ChecK Answer 1
Pls answer