Please answer 11.3 (Answer)11.1a. 2995.5kNb. 2358kNc. 2661kN11.2a. 726.33kNb. 279.6kN11.3793kN 11.3 Based on the results of Problems 11.1 and 11.2, recommend an allowable load forthe pile. Use FS = 4. 11.1 A 12 m long concrete pile is shown in Figure P11.1. Estimate the ultimate pointload Q, bya. Meyerhof's methodb. Vesic's methodc. Coyle and Castello's methodUse m = 600 in Eq. (11.26).с.Concrete pile356 mm x 356 mmLoose sanddi = 30°y = 17.5 kN/m?12 mDense sand$2 = 42°y = 18.5 kN/mFigure P11.1E,(11.26)Ра11.2 Refer to the pile shown in Figure P11.1. Estimate the side resistance Q, bya. Using Eqs. (11.40) through (11.42). Use K = 1.3 and 8' = 0.80'b. Coyle and Castello's method [Eq. (11.44)]L' = 15D(11.40)f = f=t:(11.42)2.-Κσ, tan (0.8φ') pL(11.44)||

The ultimate capacity of piles generally in cohesionless soil is achieved by the position placed on…

Answered: on the results of Problems 11.1 and…

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Civil Engineering

on the results of Problems 11.1 and 11.2, recommend an allowable load for the pile. Use FS = 4. Based

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter18: Pile Foundation

Section: Chapter Questions

Problem 18.6P

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Question

100%

Please answer 11.3

(Answer)

11.1

a. 2995.5kN

b. 2358kN

c. 2661kN

11.2

a. 726.33kN

b. 279.6kN

11.3

793kN

11.3 Based on the results of Problems 11.1 and 11.2, recommend an allowable load for
the pile. Use FS = 4.

11.1 A 12 m long concrete pile is shown in Figure P11.1. Estimate the ultimate point
load Q, by
a. Meyerhof's method
b. Vesic's method
c. Coyle and Castello's method
Use m = 600 in Eq. (11.26).
с.
Concrete pile
356 mm x 356 mm
Loose sand
di = 30°
y = 17.5 kN/m?
12 m
Dense sand
$2 = 42°
y = 18.5 kN/m
Figure P11.1
E,
(11.26)
Ра
11.2 Refer to the pile shown in Figure P11.1. Estimate the side resistance Q, by
a. Using Eqs. (11.40) through (11.42). Use K = 1.3 and 8' = 0.80'
b. Coyle and Castello's method [Eq. (11.44)]
L' = 15D
(11.40)
f = f=t:
(11.42)
2.-Κσ, tan (0.8φ') pL
(11.44)
||

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