Determine all the solutions. Find the solution that passes through the orgin y' = 2x + y + 1 x + 2y + 2
Determine all the solutions. Find the solution that passes through the orgin y' = 2x + y + 1 x + 2y + 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Determine all the solutions.
Find the solution that passes through the orgin
y'=
2x + y + 1
x + 2y + 2
X
Expert Solution
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Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question
On the picture attached..... I don't think you can pull out 1/x and mulitply it by the cx.
Isn't the x in 1/x also being raised to the power of 3/4 ??
Also, after setting it = to 0.... you raise the ln from the base of e to get e^ln = 1..... but wouldn't you raise the 0 as well to get e^0 which = 1..... not e??

Transcribed Image Text:ㅛ
x-y-1)314
2 = (imix) 20
즐
314
(a-y-isolu (onty+i) =e
(x-y-1)
Solution
Follow-up Question
After you say: "let 2h+k+1=0 and h+2k+2 = 0.....
Why did you multiply (h+2k+2) by 2 then subtract it from 2h+k+1=0 ??

Transcribed Image Text:ㅛ
Let√2h+k+1=0
h+ 2K +2=0
2h+k+ㅣ= 0
2ntukty=0
-
-35-3=0 ㅕ
k=-1
이
Solution
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