Question 5.35 5.35 On reaction with hydrogen chloride, one of the trimethylcyclohexanols shown gives asingle product, the other gives a mixture of two stereoisomers. Explain.OHT-kOHft18HOplophol is converted to the corresponding chloride at the fastest rate on reactionthe flowest rate?STO

The SN1 reaction mechanism is a sequential process in which the carbocation is first created by the elimination of the leaving group. After that, the nucleophile attacks the carbocation. In order to produce the desired product, the protonated nucleophile is finally deprotonated. The nucleophile has no effect whatsoever on this reaction's rate-determining step, which is solely dependent on the leaving group's electrophilicity.The two stereoisomers of the trimethylcyclohexanols are given as, The substrate and the reaction route affect whether a single product or a blend of two separate stereoisomers is produced. While the hydroxyl group generally behaves poorly as a leaving group, it does well in acidic media. The reaction involves protonation of the hydroxyl group followed by nucleophile assault. Chlorine can attack from either the top or bottom, producing various chemicals. Compound A has two methyl groups, which are located on the other side of the ring (in the third position), and act as a steric barrier to the attack of the chloride anion from the equatorial position.Since Compound B lacks the same kind of steric hindrance, the nucleophile attacks from both directions, resulting in a variety of products as illustrated below:The various relativities are consequently caused by where the methyl groups are located on the ring. Due to the steric hindrance of the methyl groups in the third position, compound I only form one isomer. Due to the lack of steric hindrance in the intermediate carbocation formed by compound II, the carbocation is open to nucleophile assaults from both sides.