on ore is converted to iron metal in a reaction with carbon. If 1.20 mol of Fe2O3 is used, what amounts of Fe and CO2 are produced? Fill sponses. Equation 2 Fe2O3 (s) + 3 C(s) 4 Fe(s) 3 CO2 (9) -> Initial (mol) 1.20 1.80 Change (mol) -1.20 -1.80 Numeric input field Final (mol)

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The image depicts a chemical reaction table related to the conversion of iron ore to iron metal, reacting with carbon. The equation is as follows:

\[ 2 \, \text{Fe}_2\text{O}_3(s) + 3 \, \text{C}(s) \rightarrow 4 \, \text{Fe}(s) + 3 \, \text{CO}_2(g) \]

The table is divided into three rows: Initial (mol), Change (mol), and Final (mol), with columns for each substance.

**Equation:**
- \( 2 \, \text{Fe}_2\text{O}_3(s) \)
- \( + \, 3 \, \text{C}(s) \)
- \( \rightarrow \, 4 \, \text{Fe}(s) \)
- \( + \, 3 \, \text{CO}_2(g) \)

**Initial (mol):**
- \(\text{Fe}_2\text{O}_3\) = 1.20
- \(\text{C}\) = 1.80
- \(\text{Fe}\) = 0
- \(\text{CO}_2\) = 0

**Change (mol):**
- \(\text{Fe}_2\text{O}_3\) = -1.20
- \(\text{C}\) = -1.80
- \(\text{Fe}\) = Numeric input field
- \(\text{CO}_2\) = + Numeric input field

**Final (mol):**
- \(\text{Fe}_2\text{O}_3\) = 0
- \(\text{C}\) = 0
- \(\text{Fe}\) = 0
- \(\text{CO}_2\) = 0

The table is set up to help calculate the amounts of products formed when a specific quantity of a reactant is used.
Transcribed Image Text:The image depicts a chemical reaction table related to the conversion of iron ore to iron metal, reacting with carbon. The equation is as follows: \[ 2 \, \text{Fe}_2\text{O}_3(s) + 3 \, \text{C}(s) \rightarrow 4 \, \text{Fe}(s) + 3 \, \text{CO}_2(g) \] The table is divided into three rows: Initial (mol), Change (mol), and Final (mol), with columns for each substance. **Equation:** - \( 2 \, \text{Fe}_2\text{O}_3(s) \) - \( + \, 3 \, \text{C}(s) \) - \( \rightarrow \, 4 \, \text{Fe}(s) \) - \( + \, 3 \, \text{CO}_2(g) \) **Initial (mol):** - \(\text{Fe}_2\text{O}_3\) = 1.20 - \(\text{C}\) = 1.80 - \(\text{Fe}\) = 0 - \(\text{CO}_2\) = 0 **Change (mol):** - \(\text{Fe}_2\text{O}_3\) = -1.20 - \(\text{C}\) = -1.80 - \(\text{Fe}\) = Numeric input field - \(\text{CO}_2\) = + Numeric input field **Final (mol):** - \(\text{Fe}_2\text{O}_3\) = 0 - \(\text{C}\) = 0 - \(\text{Fe}\) = 0 - \(\text{CO}_2\) = 0 The table is set up to help calculate the amounts of products formed when a specific quantity of a reactant is used.
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