On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital distance was measured to be Part A 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD68988? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Kepler's third law. Express your answer in kilograms. ? М‑ kg Submit Request Answer Part B What is the mass of HD68988? Express your answer in terms of our sun's mass. ? M = Mun Submit Request Answer

On October 15, 2001, a planet was discovered orbiting around the star HD68988. Its orbital distance was measured to be Part A 10.5 million kilometers from the center of the star, and its orbital period was estimated at 6.3 days. What is the mass of HD68988? For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Kepler's third law. Express your answer in kilograms. ? М‑ kg Submit Request Answer Part B What is the mass of HD68988? Express your answer in terms of our sun's mass. ? M = Mun Submit Request Answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A planet of mass ?=5.45×10^24 kg is orbiting in a circular path a star of mass ?=4.45×10^29 k . The radius of the orbit is ?=8.35×107^7km. What is the orbital period (in Earth days) of the planet ?planet?
A. Use the definition of the center of mass to determine the maximum “wobble” velocity of a star of mass M caused by a planet of mass m orbiting at a distance r from the star with a period T. B. Thanks to Kepler, we know that the mass, period, and distance of an orbiting object are actually related. Use Newton’s version of Kepler’s Third Law to determine the maximum “wobble” velocity in terms of M, m, and r.
A planet of mass m= 8.45 x 1024 kg is orbiting in a circular path a star of mass M= 6.95 x 1029 kg. The radius of the orbit is R= 3.15 x 107km. What is the orbital pperiod (in Earth days) of the planet Pplanet? Express your answer to three significant figures. Pplanet = ? days
A planet has been discovered orbiting the sun-like star HD 209458. From the period and velocity measured by the Doppler method, its mass was calculated to be 0.69 times that of Jupiter. The plane of the planet's orbit is edge-on and it has been observed to transit across the face of the star. The light from the star was seen to drop by 1.7% when the planet's disc lay fully within that of the star which has a radius of 8 × 10°km. Assuming that the brightness of the star is constant across the observed face, estimate the diameter of the planet and hence it density in comparison with that of Jupiter which has a radius of 7.1 × 10ʻkm. 3.
Around 2.5 centuries ago, several physicists of the time came up with the notion of a dark star. This was a star so dense, with so much gravity, that not even light could escape. The calculations used Newtonian mechanics. In class, we calculated the escape speed from the surface of the earth or the distance from the sun, and the mass of the planet or star. Here, the process is partially reversed. Calculate the dark star radius from the mass of the star and the escape speed. Answer in kilometers. c = 3*108 m/s M = 2.4*1030 kg G = 2/3 * 10-10 N*m2/kg2
do last three parts
217% ab (See #4 for Earth mass and radus 5. A satellite has an orbital radius 100 km above the Earth's surface. a. What is the speed of the satellite? b. How many minutes does it take the sātellite to complete one orbit?
A man is standing on the moon. His mass is 100 kg. The mass of the moon is 7x10^22 kg. The radius is 3.8x10^5 km. How much is the gravitational force between the man and the moon?
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Around 2.5 centuries ago, several physicists of the time came up with the notion of a dark star. This was a star so dense, with so much gravity, that not even light could escape. The calculations used Newtonian mechanics. In class, we calculated the escape speed from the surface of the earth or the distance from the sun, and the mass of the planet or star. Here, the process is partially reversed. Calculate the dark star radius from the mass of the star and the escape speed. Answer in kilometers. c = 3*108 m/s M = 3.2*1030 kg G = 2/3 * 10-10 N*m2/kg2
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter, but a mass that is only 0.43 that of Jupiter. What is the value of g on this large, but low-density, world?
Neptune has a mass of 1.0 × 1026 kg and is 4.5 × 10⁹ km from the Sun with an orbital period of 177.5 years. Planetesimals in the outer primordial solar system 4.5 billion years ago coalesced into Neptune over hundreds of millions of years. If the primordial disk that evolved into our present day solar system had a radius of 10¹1 km and if the matter that made up these planetesimals that later became Neptune was spread out evenly on the edges of it, what was the orbital period of the outer edges of the primordial disk? Express your answer rounded to the nearest year, and be sure not to do any rounding before expressing your final answer. P = years