On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.

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**Problem Statement:**

A 70 kg person walks at a steady pace of 5.0 km/h on a treadmill at a 5.0% grade. (That is, the vertical distance covered is 5.0% of the horizontal distance covered.) If we assume the metabolic power required is equal to that required for walking on a flat surface plus the rate of doing work for the vertical climb, how much power is required?

**Explanation:**

This problem involves calculating the power output required for a person to walk on a treadmill with a specific incline. It considers both the energy needed to walk on a flat surface and the additional energy required to overcome the incline.

To solve the problem, the following aspects should be evaluated:

1. **Power for Flat Surface:**
   - Determine the power needed for walking at 5.0 km/h on a flat surface.

2. **Power for Incline:**
   - Identify the rate of energy required to climb vertically since the treadmill is at a 5.0% grade. This involves calculating the vertical component of the walking speed and converting that into a power requirement.

3. **Total Power:**
   - Sum the power for the flat surface and the power for the incline to get the total power required.

**Note:** The formula for calculating the power due to the incline is generally derived from the relationship: Power = work done/time, where work done is the force exerted (weight of the person) times the vertical distance covered.
Transcribed Image Text:**Problem Statement:** A 70 kg person walks at a steady pace of 5.0 km/h on a treadmill at a 5.0% grade. (That is, the vertical distance covered is 5.0% of the horizontal distance covered.) If we assume the metabolic power required is equal to that required for walking on a flat surface plus the rate of doing work for the vertical climb, how much power is required? **Explanation:** This problem involves calculating the power output required for a person to walk on a treadmill with a specific incline. It considers both the energy needed to walk on a flat surface and the additional energy required to overcome the incline. To solve the problem, the following aspects should be evaluated: 1. **Power for Flat Surface:** - Determine the power needed for walking at 5.0 km/h on a flat surface. 2. **Power for Incline:** - Identify the rate of energy required to climb vertically since the treadmill is at a 5.0% grade. This involves calculating the vertical component of the walking speed and converting that into a power requirement. 3. **Total Power:** - Sum the power for the flat surface and the power for the incline to get the total power required. **Note:** The formula for calculating the power due to the incline is generally derived from the relationship: Power = work done/time, where work done is the force exerted (weight of the person) times the vertical distance covered.
On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.
Transcribed Image Text:On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.
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