On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.
On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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![**Problem Statement:**
A 70 kg person walks at a steady pace of 5.0 km/h on a treadmill at a 5.0% grade. (That is, the vertical distance covered is 5.0% of the horizontal distance covered.) If we assume the metabolic power required is equal to that required for walking on a flat surface plus the rate of doing work for the vertical climb, how much power is required?
**Explanation:**
This problem involves calculating the power output required for a person to walk on a treadmill with a specific incline. It considers both the energy needed to walk on a flat surface and the additional energy required to overcome the incline.
To solve the problem, the following aspects should be evaluated:
1. **Power for Flat Surface:**
- Determine the power needed for walking at 5.0 km/h on a flat surface.
2. **Power for Incline:**
- Identify the rate of energy required to climb vertically since the treadmill is at a 5.0% grade. This involves calculating the vertical component of the walking speed and converting that into a power requirement.
3. **Total Power:**
- Sum the power for the flat surface and the power for the incline to get the total power required.
**Note:** The formula for calculating the power due to the incline is generally derived from the relationship: Power = work done/time, where work done is the force exerted (weight of the person) times the vertical distance covered.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9628995d-cca1-4807-a778-f4231868ca8a%2F36a1e5b2-e183-446b-9404-c60eb4f7f2ca%2Fh07bzzf_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A 70 kg person walks at a steady pace of 5.0 km/h on a treadmill at a 5.0% grade. (That is, the vertical distance covered is 5.0% of the horizontal distance covered.) If we assume the metabolic power required is equal to that required for walking on a flat surface plus the rate of doing work for the vertical climb, how much power is required?
**Explanation:**
This problem involves calculating the power output required for a person to walk on a treadmill with a specific incline. It considers both the energy needed to walk on a flat surface and the additional energy required to overcome the incline.
To solve the problem, the following aspects should be evaluated:
1. **Power for Flat Surface:**
- Determine the power needed for walking at 5.0 km/h on a flat surface.
2. **Power for Incline:**
- Identify the rate of energy required to climb vertically since the treadmill is at a 5.0% grade. This involves calculating the vertical component of the walking speed and converting that into a power requirement.
3. **Total Power:**
- Sum the power for the flat surface and the power for the incline to get the total power required.
**Note:** The formula for calculating the power due to the incline is generally derived from the relationship: Power = work done/time, where work done is the force exerted (weight of the person) times the vertical distance covered.
![On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9628995d-cca1-4807-a778-f4231868ca8a%2F36a1e5b2-e183-446b-9404-c60eb4f7f2ca%2Fqsmeflm_processed.png&w=3840&q=75)
Transcribed Image Text:On flat ground, a 70 kg person requires about 300 W of metabolic power to walk at a steady pace of 5.0 km/h (1.4 m/s). Using the same metabolic power output, that person can bicycle over the same ground at 15 km/h.
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