On February 20, 2018 ncbnews.com ran a story titled "Poll: Support for gun control hits record high." This article references a survey performed by Quinnipiac University of 1,351 voters nationwide and of those sampled 883 stated that they wan stricter gun control laws. Assume that the survey utilized a random sample of all Americans. You are going to compute and thoroughly interpret a 95% confidence interval for the proportion of all Americans that want stricter gun control laws. Calculate the margin of error for this confidence interval (round to four decimal spots). a, 0.0332 b. 0.0253 c. 0.0258 d. 0.0212

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On February 20, 2018, nbcnews.com ran a story titled “Poll: Support for gun control hits record high.” This article references a survey performed by Quinnipiac University of 1,351 voters nationwide, and of those sampled, 883 stated that they want stricter gun control laws. Assume that the survey utilized a random sample of all Americans. You are going to compute and thoroughly interpret a 95% confidence interval for the proportion of all Americans that want stricter gun control laws.

Calculate the margin of error for this confidence interval (round to four decimal spots).

- a. 0.0332
- b. 0.0253
- c. 0.0258
- d. 0.0212
Transcribed Image Text:On February 20, 2018, nbcnews.com ran a story titled “Poll: Support for gun control hits record high.” This article references a survey performed by Quinnipiac University of 1,351 voters nationwide, and of those sampled, 883 stated that they want stricter gun control laws. Assume that the survey utilized a random sample of all Americans. You are going to compute and thoroughly interpret a 95% confidence interval for the proportion of all Americans that want stricter gun control laws. Calculate the margin of error for this confidence interval (round to four decimal spots). - a. 0.0332 - b. 0.0253 - c. 0.0258 - d. 0.0212
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