On combustion of 6.853 mg of a human sex hormone, 19.78 mg CO2 and 6.410 mg H2O were obtained. Assuming only carbon, hydrogen and oxygen are present in this compound and the molecular formula is twice the empirical formula, which of the following is its molecular formula?

Q: A particular protein sample is found to have 1 atom of iron in its chemical formula. If the mass…

A: Mass percent expresses the solute concentration in any mixture. The division of weight of dissolved…

Q: Combustion analysis was performed on 1.50 g of a compound containing C, H and N to yield 3.21 g of…

A: Given,  Mass of the compound = 1.50 g  Mass of CO2 = 3.21 g  Mass of H2O = 0.981 g  Empirical…

Q: Acetaminophen has a elemental composition of 63.56% carbon, 6.00% hydrogen, 9.27% nitrogen and…

A: Step 1: carbon elemental composition /12, hydrogen composition /1, nitrogen composition /14, oxygen…

Q: A particular carborane has the following mass percentages: 26.35%C and 59.28%B. What is the…

A:

Q: When 1.615 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.545 grams…

A: The molecular formula is a formula generated from molecules that represents the total number of…

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 13.51 g H2O. Calculate the empirical…

A: Solution Given data, The amount of CO2 = 33.01g The amount of H2O = 13.52g Number of moles of…

Q: What is the molecular formula of a compound with the empirical formula CH2CH2 and a formula mass of…

A: Empirical formula of compound=CH2 Mass of empirical formula=1 x atomic mass of C + 2 x atomic mass…

Q: What is the molecular formula of a compound with the empirical formula CH2OCH2O and a formula mass…

A:

Q: When 4.510 grams of a hydrocarbon, CHy, wvere burned in a combustion analysis apparatus, 14.15 grams…

A: Whenever the combustion f a hydrocarbon takes place, only carbon dioxide and water vapors are…

Q: 0.333 g of a hydrocarbon (CxHy) was analyzed by combustion analysis and 1.009 g of CO2 (MM = 44.01…

A:

Q: In 1871, Mendeleev predicted the undiscovered element ekasilicon. In 1886, the element was…

A:

Q: Combustion analysis of 60.0 grams of a C, H and O containing compound produced 161.41 grams of…

A: Combustion: Burning of any substance in the  presence of oxygen is called combustion. As combustion…

Q: What is the empirical formula for a compound when nitrogen is 1.121 g, hydrogen 0.161 g, carbon is…

A: Empirical formula :-  The chemical formula which shows only the relative number (simplest ratio) of…

Q: Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.1422 g of…

A: Answer: emperial formula of the Hydrocarbon compound is C2H5

Q: 0 g of a pure hydrocarbon was combusted in oxygen. The reaction was a complete combustion.  This…

A: Hydrocarbons are the compounds of carbon and hydrogen only. On combustion, hydrocarbons produce…

Q: Butanol is 64.81% carbon, 21.59% oxygen, and 13.60% hydrogen by mass. What is the molecular formula…

A: Given that the Butanol is 64.81% carbon, 21.59 % oxygen and 13.60 % hydrogen by mass. The molar mass…

Q: When 6.360 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.50 grams…

A:

Q: A 3.260 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A:

Q: Combustion analysis of a hydrocarbon produced 33.01 g CO2 and 4.83 g H2O. Calculate the empirical…

A: Given : Mass of CO2 produced = 33.01 g Mass of H2O produced = 4.83 g And the compound is…

Q: When 4.993 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.67 grams…

A:

Q: Combustion analysis of an unknown compound containing only carbon and hydrogen produced 0.2845 g of…

A:

Q: When 5.347 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 16.38 grams…

A: Empirical formula can be determined from the moles of gases formed of CO2 and H2O

Q: What is the empirical formula of a compound that contains 72.46% carbon, 6.09% hydrogen, and the…

A:

Q: What are the empirical formula and empirical formula mass for C3H9O3?

A: Given molecule is                          C3H9O3

Q: In a lab experiment, it was observed that 68.84 g of lead combines with 23.56 g of chlorine to form…

A: Given :-  mass of lead = 68.84 g  mass of chlorine = 23.56 g  molar mass = 834 g  To determine :-…

Q: What is the molecular formula of a compound

A: Given :- molar mass of compound  = 220 g/mol            Empirical formula = P2O3.  To find :…

Q: Part D. A 28.50 g sample of a compound of carbon, sulfur, hydrogen, and combusted (burned). 35.25 g…

A:

Q: A binary compound of boron and hydrogen has the following mass composition: 78.14% boron, 21.86%…

A: Determine how many grams of each element are present in  of compound. Given compound has  boron (by…

Q: A compound with an empirical formula of C8H4NNaO4S is found to have a molar mass twice that of the…

A: Empirical formula :-  The formula which shows only relative number (simple ratio) of atoms of…

Q: Pyrazole is an organic compound. Determine the molecular formula of pyrazole if it is 52.93 %…

A: Given data,% of C=52.93%% of H=5.92%% of N=41.15%Molar mass of pyrazole=68.07726g/mol

Q: Analysis of a carbohydrate showed that it consisted of 40.0 % C, 6.71 % H, and 53.3 % O by mass. Its…

A: The objective of this question is to determine the molecular formula of a carbohydrate based on its…

Q: A 2.260 gram sample of an organic compound containing C,H, and O is analyzed by combustion analysis…

A: Empirical formula represents the simplest whole number ratio of atoms of elements present in the…

Q: A 7.194 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: We have to predict the empirical and molecular formula.Given, The mass of organic compound = 7.194…

Q: What is the mass percent composition of oxygen in a compound having the empirical formula C20H34O4?

A:

Q: A 4.600 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: Empirical formula: An empirical formula is a chemical formula that does not indicate the entire…

Q: What is the molecular formula of a compound with the empirical formula CH2O and a formula mass of…

A: Empirical formula of compound=CH2O Mass of empirical formula=1 x atomic mass of C + 2 x atomic mass…

Q: Analysis of a 20.0-gram sample of a compound containing only calcium and bromine indicates that 4.00…

A: given  mass of sample = 20 g mass of calcium = 4 g

Q: Combustion analysis of 63.8 mg of a C, H and O containing compound produced 145.0 mg of CO, and…

A: In above question the empirical formula can be calculate with known of percentage composition of…

Q: A 2.664 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: Consider the given information is as follows;Mass of the organic compound sample = 2.664 gMass of  =…

Q: When 2.666 grams of a hydrocarbon, C,H,, were burned in a combustion analysis apparatus, 7.803 grams…

A: Mass of hydrocarbon = 2.666 g Mass of CO2 = 7.803 g Mass of H2O = 4.792 g Molar mass of compund =…

Q: When 2.375 grams of a hydrocarbon CxHy, we're burned in a combustion analysis apparatus, 7.451 grams…

A:

Q: An industrial detergent was found to be composed of 57.72% C, 8.073% H, 17.09% O, by mass and the…

A: Let's assume, the empirical molecular formula of the given compound is CaHbOcX2c. 'a' is the no of…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.