On average, Americans have lived in 2 places by the time they are 18 years old. Is this average a different number for college students? The 63 randomly selected college students who answered the survey question had lived in an average of 1.97 places by the time they were 18 years old. The standard deviation for the survey group was 0.4. What can be concluded at the  αα = 0.10 level of significance? The null and alternative hypotheses would be:       H0:H0:  ? p μ  Select an answer = < > ≠         H1:H1:  ? p μ  Select an answer ≠ > < =     The test statistic ? t or z  =     (please show your answer to 3 decimal places.) The p-value =    (Please show your answer to 4 decimal places.) Interpret the p-value in the context of the study. If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 63 college students, then there would be a 55.38136608% chance that the sample mean for these 63 college students would either be less than 1.97 or greater than 2.03. There is a 55.38136608% chance of a Type I error. If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 63 college students then there would be a 55.38136608% chance that the population mean would either be less than 1.97 or greater than 2.03. There is a 55.38136608% chance that the population mean number of places that college students lived in by the time they were 18 years old is not equal to 2.

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On average, Americans have lived in 2 places by the time they are 18 years old. Is this average a different number for college students? The 63 randomly selected college students who answered the survey question had lived in an average of 1.97 places by the time they were 18 years old. The standard deviation for the survey group was 0.4. What can be concluded at the  αα = 0.10 level of significance?

  1. The null and alternative hypotheses would be:     

 H0:H0:  ? p μ  Select an answer = < > ≠       

 H1:H1:  ? p μ  Select an answer ≠ > < =    

  1. The test statistic ? t or z  =     (please show your answer to 3 decimal places.)
  2. The p-value =    (Please show your answer to 4 decimal places.)
  3. Interpret the p-value in the context of the study.
    • If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 63 college students, then there would be a 55.38136608% chance that the sample mean for these 63 college students would either be less than 1.97 or greater than 2.03.
    • There is a 55.38136608% chance of a Type I error.
    • If the population mean number of places that college students lived in by the time they were 18 years old is 2 and if you survey another 63 college students then there would be a 55.38136608% chance that the population mean would either be less than 1.97 or greater than 2.03.
    • There is a 55.38136608% chance that the population mean number of places that college students lived in by the time they were 18 years old is not equal to 2.
Expert Solution
Step 1

Given information-

Population mean, μ = 2

Sample size, n = 63

Sample mean, x-bar = 1.97

Sample standard deviation, s = 0.4

Significance level, α = 0.1

For this steady we will use two tailed t-test statistics.

We have to test the claim that this average is different for college students.

Hypothesis Formulation-

Null Hypothesis, H0: μ = 2

Alternate Hypothesis, Ha: μ ≠ 2

Since here population standard deviation is unknown so using t-test statistics.

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