On Apollo missions to the Moon, the command module orbited at analtitude of 110 km above the lunar surface.Part AHow long did it take for the command module to complete one orbit?► View Available Hint(s)Π ΑΣΦT =SubmitProvide Feedbackwww?h

We are given the altitude of satellite. We first find the gravitational force between satellite and moon. This provides necessary centripetal force. We equate both to find the angular velocity. We then find the time period.Altitude h=110km=110000m Radius of moon is R=1737.4km=1737400m Hence the radius of orbit is r=R+hr=1737.4+110r=1847.4kmr=1847400m Mass of moon is M=7.35×1022kg Let mass of satellite be m. Hence the gravitational force is F=GMmr2 Hence, mω2r=GMmr2ω2=GMr3ω=GMr32πT=6.67×10-11×7.35×1022184740032πT=77.6×10-4T=2π77.6×10-4T=7131.13 secs Hence time taken is 7137.13 secs or 1.98 hours.

Answered: On Apollo missions to the Moon, the…

On Apollo missions to the Moon, the command module orbited at an altitude of 110 km above the lunar surface. Part A How long did it take for the command module to complete one orbit? ► View Available Hint(s) ΤΙ ΑΣΦ T = Submit Provide Feedback ? h