On an MAT102 test Catherine presented the following argument: "To prove that q: ZxZZ, q(x, y) = = x +y is surjective, we first choose any m € Z. Then we set x = 1 and y = m - 1. Since q (x, y) = x+y=1+(m-1) = m, this implies that q is a surjective function." What can be concluded about this proof? [Select]
On an MAT102 test Catherine presented the following argument: "To prove that q: ZxZZ, q(x, y) = = x +y is surjective, we first choose any m € Z. Then we set x = 1 and y = m - 1. Since q (x, y) = x+y=1+(m-1) = m, this implies that q is a surjective function." What can be concluded about this proof? [Select]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please find attached problem. The drop-down menu says (1) The proof is correct. (2) The proof is not valid since values for x and y are chosen incorrectly. (3) The proof is incorrect since we cannot specify the values of the variables without loosing generality of the proof. Please chose one of those options. Thank you
![On an MAT102 test Catherine presented the following argument:
"To prove that q: Z× Z → Z, q(x, y) = x +y is surjective, we first choose any m € Z.
Then we set x = 1 and y = m - 1.
Since q (x, y) = x+y=1+(m− 1) = m, this implies that q is a surjective function."
What can be concluded about this proof? [Select]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F658d0877-d30e-470e-a192-6c902c3b5487%2Fca9d25c5-924e-4384-a71b-d06ee678c893%2Frmo4ejs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:On an MAT102 test Catherine presented the following argument:
"To prove that q: Z× Z → Z, q(x, y) = x +y is surjective, we first choose any m € Z.
Then we set x = 1 and y = m - 1.
Since q (x, y) = x+y=1+(m− 1) = m, this implies that q is a surjective function."
What can be concluded about this proof? [Select]
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