On a popular app, users rate hair salons as 1, 2, 3, 4, or 5 stars. Suppose a rating is randomly selected from all the ratings on the app. Let X be the numberof stars of the selected rating. Here is the probability distribution of X.12345Value x of XP(X=x) 0.26 0.18 0.09 0.22 0.25For parts (a) and (b) below, find the probability that the randomly selected hair salon rating has the described number of stars.(a) Fewer than 3:(b) More than 3:0SWE

Answered: Image /qna-images/answer/82faa18f-06fa-439f-a986-14cb376b6b20.jpg

Answered: On a popular app, users rate hair…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The following is the probability distribution for an athlete of winning medals. Medal (Event) Gold E1 Silver E2 Bronze E3 No medal E4 P(Ei) 0.10 0.15 0.20 0.55 Find the probability of earning a medal. Group of answer choices 0.45 0.9 0.15 0.75 0.25
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
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Refer to this figure to answer number 8- 10. The table below show the probability distribution of number of face mask sold per day. 1 2 3 5 6. 7 8. 10 0.07 P(x) P/x) 0.16 0.07 0.1 0.09 0.1 0.07 0.08 0.1 0.17 0.56 1.4 1.96 5.76 11.56 0.16 0.40 0.16 0.14 0.3 0.36 0.5 0.42 0.56 0.9 1.7 X-U -4.6 -3.6 -2.6 -1.6 -0.6 0.4 2.4 3.4 4.4 (x-)A2 (x-u)A2 *P(x) 21.16 12.96 6.76 2.56 0.36 0.16 19.36 3.39 0.91 0.68 0.23 0.04 0.01 1.16 3.29 8. What is ExP(x) =? A. 5.6 B. 6.5 C.7 D. 8 9. What is a? = E[(x - 4) P(x)] A. 5.9 %3D В. 8.6 С. 10.25 D. 11.35 10. If the standard deviation of the variance of problem number 9 is 3.20156, then how do we get the value of standard deviation given the value of variance? A. Vo? B. Va C. uP(x) D. o ololo-
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Answer 1&2 plz
Megan has purchased the insurance policy from an insurance company to cover the value of hers new car in case if it gets totaled for the price of $1500 per year. Megan's car worth $20000 and the probability of her totaling the car during the length of the policy is estimated to be 0.4%. Let XX be the insurance company's profit. Answer the following questions: 1. Create the probability distribution table for XX : XX outcome profit xx ,$ P(X=x)P(X=x) car is totaled car is not totaled 2. Use the probability distribution table to find the following: E[X]=μX=E[X]=μX= dollars. (Round the answer to 1 decimal place.) SD[X]=σX=SD[X]=σX= dollars. (Round the answer to 1 decimal place.)
Suppose that x represents the number of cars sold at a dealership in a randomly selected single day. The probability distribution of x is given in the table below. 4 5 7 8 9 10 p(x) 0.03 0.08 0.19 0.31 0.22 0.13 0.04 If you wish, you can click to download the data in your preferred format. CrunchIt! CSV Excel JMP Mac Text Minitab PC Text R SPSS TI Calc What is the mean number of cars, u, sold per day at the dealership? Give your answer decimal form precise to two decimal places. cars
Answer number 3
A car service centre studies the record that shows the number of cars serviced per day. They uses the data to calculate the relative frequencies and obtains the following probability distribution. Number of cars, x P(X = x) 1 3 4 5 0.1 0.1 0.2 0.3 0.2 0.1 Find the probability that two or less cars are serviced each day. O 0.6 O 0.3 О 02 O 0.4
if the following table is probability distribution . Find the mean (E(X))? 1 4 P(X=x) 16/81 32/81 24/81 8/81 1/81 Select one: a. 4 o b. 112 81 106 C. 81 d. 14 3

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