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On a mini golf course, a golf ball rolls horizontally at a speed of Vo into a loop (cut through cylinder), which forces the ball into a vertical circular motion as shown in the drawing. Cylinder radius is as shown in the drawing R. The acceleration of gravity is g. The mass of the golf ball is irrelevant to the solution of the task. You can ignore from friction loss, air resistance m.m. The mechanical energy is conserved throughout the movement.

On a mini golf course, a golf ball rolls horizontally at a speed of Vo into a loop (cut through cylinder), which forces the ball into a vertical circular motion as shown in the drawing. Cylinder radius is as shown in the drawing R. The acceleration of gravity is g. The mass of the golf ball is irrelevant to the solution of the task. You can ignore from friction loss, air resistance m.m. The mechanical energy is conserved throughout the movement.

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Question 3 On a mini golf course, a golf ball rolls horizontally at a speed of Vo into a loop (cut through cylinder), which forces the ball into a vertical circular motion as shown in the drawing. Cylinder radius is as shown in the drawing R. The acceleration of gravity is g. The mass of the golf ball is irrelevant to the solution of the task. You can ignore from friction loss, air resistance m.m. The mechanical energy is conserved throughout the movement. R h vo 450 R -> datum + Xo It is stated that the ball can just move around in the circular loop without dropping the wall, it will say Vo is the minimum starting speed that allows the full circular motion. 1) Draw free play diagram (FLD) and kinetic diagram (KD) of the sphere at the apex of the circle loop. 2) Determine the initial velocity of the sphere vo (expressed by R and g) After the ball has passed the loop, it continues up a ramp with a slope of 45 ° in relation to horizontal. At altitude R the ramp ends and the ball continues in free fall and lands at point xn. 3) Calculate the height h above the date of the vertex of the drop parabola (expressed by R). 4) Calculate the distance of the point of impact (xn) from the end point of the ramp, xn-Xo (expressed by R)
Transcribed Image Text:Question 3 On a mini golf course, a golf ball rolls horizontally at a speed of Vo into a loop (cut through cylinder), which forces the ball into a vertical circular motion as shown in the drawing. Cylinder radius is as shown in the drawing R. The acceleration of gravity is g. The mass of the golf ball is irrelevant to the solution of the task. You can ignore from friction loss, air resistance m.m. The mechanical energy is conserved throughout the movement. R h vo 450 R -> datum + Xo It is stated that the ball can just move around in the circular loop without dropping the wall, it will say Vo is the minimum starting speed that allows the full circular motion. 1) Draw free play diagram (FLD) and kinetic diagram (KD) of the sphere at the apex of the circle loop. 2) Determine the initial velocity of the sphere vo (expressed by R and g) After the ball has passed the loop, it continues up a ramp with a slope of 45 ° in relation to horizontal. At altitude R the ramp ends and the ball continues in free fall and lands at point xn. 3) Calculate the height h above the date of the vertex of the drop parabola (expressed by R). 4) Calculate the distance of the point of impact (xn) from the end point of the ramp, xn-Xo (expressed by R)
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