Draw the starting structure that would lead to these major products. **Chemical Reaction Process:**1. **Reagents:** - **Step 1:** mCPBA - **Step 2:** \( \text{H}_3\text{O}^+ \)2. **Product:** - The resulting compound is a molecule with two hydroxyl groups (OH) attached to a carbon chain. The hydroxyl groups are shown with wedge bonds, indicating they are on the same side of the molecule.**Explanation:**- The use of mCPBA, a peracid, suggests an epoxidation step. This is typically followed by acid-catalyzed ring opening using \( \text{H}_3\text{O}^+ \), which results in the formation of a diol. **Visual Diagram:**- A carbon chain is depicted with two angular bonds representing secondary carbon atoms, each bonded to an -OH group. This molecular structure indicates a syn-diol, where both hydroxyl groups are on the same face of the molecule.

Given that, the reaction is:When an alkene reacts with meta-chloroperoxybenzoic acid (mCPBA), it undergoes an epoxidation reaction. The reaction involves the formation of an epoxide, which is a three-membered ring containing an oxygen atom. Next, the epoxide reacts with to give cis-diol as a final product.The stereochemistry of this reaction is always retained. That is, a cis alkene will give the cis-epoxide, and a trans alkene will give a trans epoxide.Then, the mechanism of the given reaction is: Therefore, the structure of the reactant is: