Find the ff; Moment of Inertia (Ix, Iy), Section Modulus (Sx, Sy) & Radius of Gyration (Rx & Ry). Show detailed and complete solution. Compute for Ix, ly, Sx, Sy, rx and ry..A built up section consists of two miscellaneous channels MC 18 x 42.7 and onecover plate 12 mm x 500 mm. The channels are placed at 300 mm. back to back withthe flanges outstanding. This section is used as a column having a height of 6 m.Assume K = 1.0Properties of one MC 18 x 42.7A = 8129.02 mm²d = 450 mmbf= 100.33 mmtf = 15.88 mmtw 11.43 mm== 230.59 x 106 mm4= 5.99 x 106 mm4Tx=168.66 mmSy=1009.44 x 10³ mm³X = 22.28 mmx462 mm500 mm300 mm12112 mm

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ömpute for Ix, ly, Sx, Sy, rx and ry.. A built up section consists of two miscellaneous channels MC 18 x 42.7 and on over plate 12 mm x 500 mm. The channels are placed at 300 mm. back to back wit he flanges outstanding. This section is used as a column having a height of 6 m ssume K= 1.0 Properties of one MC 18 x 42.7 A = 8129.02 mm² d = 450 mm bf= 100.33 mm tf= 15.88 mm tw = 11.43 mm Ix=230.59 x 106 mm 4 = 5.99 x 106 mm4 ly Tx=168.66 mm -x 462 mm 500 mm 12 mm

ömpute for Ix, ly, Sx, Sy, rx and ry.. A built up section consists of two miscellaneous channels MC 18 x 42.7 and on over plate 12 mm x 500 mm. The channels are placed at 300 mm. back to back wit he flanges outstanding. This section is used as a column having a height of 6 m ssume K= 1.0 Properties of one MC 18 x 42.7 A = 8129.02 mm² d = 450 mm bf= 100.33 mm tf= 15.88 mm tw = 11.43 mm Ix=230.59 x 106 mm 4 = 5.99 x 106 mm4 ly Tx=168.66 mm -x 462 mm 500 mm 12 mm

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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