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OMe + 1,00 Pd(PPh3)4 (cat.) CO₂Me N THF, 30 °C 92% n. *0. хазать H3CO OCH3 *p. t-BuO₂C Ph OH (Ph3P)2PdCl2 (cat.) о CO (4 atm) 78% K2CO3, DMF, 50 °C Et 1a. LHMDS, THF, -78 °C 1b. Tf₂NPh 2. H2, PtO2 (cat.), t-BuOH P 87%

OMe + 1,00 Pd(PPh3)4 (cat.) CO₂Me N THF, 30 °C 92% n. *0. хазать H3CO OCH3 *p. t-BuO₂C Ph OH (Ph3P)2PdCl2 (cat.) о CO (4 atm) 78% K2CO3, DMF, 50 °C Et 1a. LHMDS, THF, -78 °C 1b. Tf₂NPh 2. H2, PtO2 (cat.), t-BuOH P 87%

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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OMe + 1,00 Pd(PPh3)4 (cat.) CO₂Me N THF, 30 °C 92% n. *0. хазать H3CO OCH3 *p. t-BuO₂C Ph OH (Ph3P)2PdCl2 (cat.) о CO (4 atm) 78% K2CO3, DMF, 50 °C Et 1a. LHMDS, THF, -78 °C 1b. Tf₂NPh 2. H2, PtO2 (cat.), t-BuOH P 87%
Transcribed Image Text:OMe + 1,00 Pd(PPh3)4 (cat.) CO₂Me N THF, 30 °C 92% n. *0. хазать H3CO OCH3 *p. t-BuO₂C Ph OH (Ph3P)2PdCl2 (cat.) о CO (4 atm) 78% K2CO3, DMF, 50 °C Et 1a. LHMDS, THF, -78 °C 1b. Tf₂NPh 2. H2, PtO2 (cat.), t-BuOH P 87%
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