Om 10m 20m 17.07m 0ATUM Y=18.86KN/m K = 10*m/sec B %3D Impervious (a) The elevation head, total head, and pressure head at B. (b) The pore water pressure at B. (c) The exit hydraulic gradient (iesit) and the critical hydraulic gradient (i«). (d) Determine the factor of safety against a quick sand condition. Hint: (1) For the iexit calculation, choose the least water flow length, L. (2) FOS = iexit / ic, where if FOS is less than 4, the quick condition occurs %3D 18.60m 12.80m 9.14m

Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter6: Hydraulic Conductivity
Section: Chapter Questions
Problem 6.1P
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Om
10m
20m
17.07m
DATUM
Ye=18.86KN/m³
K = 10*m/sec
Impervious
(a) The elevation head, total head, and pressure head at B.
(b) The pore water pressure at B.
(c) The exit hydraulic gradient (iexit) and the critical hydraulic gradient (ier).
(d) Determine the factor of safety against a quick sand condition.
Hint:
(1) For the iexit calculation, choose the least water flow length, L.
(2) FOS = iexit / iç where if FOS is less than 4, the quick condition occurs
%3D
18.60m
12.80m
9.14m
Transcribed Image Text:Om 10m 20m 17.07m DATUM Ye=18.86KN/m³ K = 10*m/sec Impervious (a) The elevation head, total head, and pressure head at B. (b) The pore water pressure at B. (c) The exit hydraulic gradient (iexit) and the critical hydraulic gradient (ier). (d) Determine the factor of safety against a quick sand condition. Hint: (1) For the iexit calculation, choose the least water flow length, L. (2) FOS = iexit / iç where if FOS is less than 4, the quick condition occurs %3D 18.60m 12.80m 9.14m
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