Solve the problem.10) Scores on a test are normally distributed with a mean of 65.3 and a standard deviation of 10.3. FindP81, which separates the bottom 81% from the top 19%.A) 0.88B) 68.3C) 74.4D) 0.29110)

Given data Normal distribution Population mean (μ) = 65.3 Population standard deviation (σ) = 10.3…

Answered: olve the problem. 10) Scores on a test…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the 1992 presidential election, Alaska's 40 election districts averaged 1824 votes per district for President Clinton. The standard deviation was 573. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 1824 a population mean or a sample mean? c. Find the probability that a randomly selected district had fewer than 1872 votes for President Clinton. d. Find the probability that a randomly selected district had between 1842 and 2091 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
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Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. Click the icon to view the data table. The mean is u= girl(s). (Round to one decimal place as needed.) The standard deviation is o = e# girl(s). (Round to one decimal place as needed.) Table of numbers of girls and probabilities Number of Girls x 0 1 2 3 4 5 6 7 8 átv P(x) 0.004 0.034 0.117 0.218 0.278 0.217 0.102 0.027 0.003 D - X NiZ Next
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How can I analyze these graphs?
Researchers collected information on the body parts of a new species of frog. The thumb length for the female frog has a mean of 8.28 mm and a standard deviation of 0.78 mm. Let x denote thumb length for a female specimen. a. Find the standardized version of x. b. Determine and interpret the z-scores for thumb lengths of 10.3 mm and 7.1 mm. Round your answers to two decimal places. a. Find the standardized version of x. z=enter your response here
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olve the problem. 10) Scores on a test are normally distributed with a mean of 65.3 and a standard deviation of 10.3. Find P81, which separates the bottom 81% from the top 19%. A) 0.88 B) 68.3 C) 74.4 D) 0.291