olve the problem by using Pearson r.

What is the p-value for the test statistic?A) 0.0165B) 0.0188803968C) 0.168D) 0.0085E) 0.0022854202

A chi-square test for homogeneity was conducted to investigate whether the four high schools in a school district have different absentee rates for each of four grade levels. The chi-square test statistic and p-value of the test were 19.02 and 0.025, respectively. Which of the following is the correct interpretation of the p-value in the context of the test?  a Assuming that each high school has a different absentee rate for each grade level, there is a 2.5 percent chance of finding a test statistic 19.02 or larger.  b Assuming that each high school has the same absentee rate for each grade level, there is a 2.5 percent chance of finding a test statistic 19.02 or smaller.  c Assuming that each high school has the same absentee rate for each grade level, there is a 2.5 percent chance of finding a test statistic 19.02 or larger.  d There is a 2.5 percent chance that the absentee rate for each grade level at the four schools is the same.  e There is a 2.5…

A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage).  Statistic Test Group Control Group   Mean Damage X⎯⎯⎯1X¯1 = $ 1,188   X⎯⎯⎯2X¯2 = $ 1,792   Sample Std. Dev. s1 = $ 712   s2 = $ 800   Repair Incidents n1 =   16   n2 =   14      Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 95 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 95% confidence interval is from  to  (b) Repeat part (a), using the assumption of unequal variances with Welch's…

A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage).  Statistic Test Group Control Group   Mean Damage X⎯⎯⎯1X¯1 = $ 1,245   X⎯⎯⎯2X¯2 = $ 1,790   Sample Std. Dev. s1 = $ 721   s2 = $ 835   Repair Incidents n1 =   17   n2 =   14      Source: Unpublished study by Thomas W. Lauer and Floyd G. Willoughby. (a) Construct a 99 percent confidence interval for the true difference of the means assuming equal variances. (Round your final answers to 3 decimal places. Negative values should be indicated by a minus sign.) The 99% confidence interval is from  to  (b) Repeat part (a), using the assumption of unequal variances with Welch's…

The Trial Urban District Assessment (TUDA) is a government-sponsored study of student achievement in large urban school districts. TUDA gives a mathematics test scored from 0 to 500. A score of 262 is a "basic" mathematics level, and a score of 299 is "proficient." Scores for a random sample of 1100 eighth-graders in Dallas had x = 264 with standard error 1.3. TUDA results for 2019 from the National Center for Education Statistics, at https://www.nationsreportcard.gov. O Macmillan Learning (a) We don't have the 1100 individual scores, but use of the t procedures is surely safe. Why? O Because the data has a strong skew. O Because the sample size is very large. O Because use of the t procedures is always safe. O Because the sample doesn't have outliers.

The Trial Urban District Assessment (TUDA) is a government-sponsored study of student achievement in large urban school districts. TUDA gives a mathematics test scored from 0 to 500. A score of 262 is a "basic" mathematics level, and a score of 299 is "proficient." Scores for a random sample of 1100 eighth-graders in Dallas had x = 264 with standard error 1.3. TUDA results for 2019 from the National Center for Education Statistics, at https://www.nationsreportcard.gov. LO 5 DEC 1 S tv ♫ ♫ O Macmillan Learning (c) Is there good evidence that the mean for all Dallas eighth-graders is different from the basic level? F8 OYes, because the sample mean of 264 is not included in the 99% confidence interval. Yes, because the basic level of 262 is not included in the 99% confidence interval. O No, because the basic level of 262 is included in the 99% confidence interval. O No, because the sample mean of 264 is included in the 99% confidence interval. N 1917 66 7 A 72 P GE zoom

The Trial Urban District Assessment (TUDA) is a government-sponsored study of student achievement in large urban school districts. TUDA gives a mathematics test scored from 0 to 500. A score of 262 is a "basic" mathematics level, and a score of 299 is "proficient." Scores for a random sample of 1100 eighth-graders in Dallas had x = 264 with standard error 1.3. TUDA results for 2019 from the National Center for Education Statistics, at https://www.nationsreportcard.gov. O Macmillan Learning (b) Identify a 99% confidence interval for the mean score of all Dallas eighth-graders. (Be careful: the report gives the standard error of x, not the standard deviation s.) O 261.9 to 266.1 O260.6 to 267.4 O261.4 to 266.6 O 262.7 to 265.3

What is the portability of observing a z score between 2 and 3?

An experiment to investigate the effect of 4 diets on milk yield was conducted using a standard latin square design as follows. There were 4 cows available for the experiment. For each of the 4 lactation periods the cows received a different diet. Below is an incomplete table of the ANOVA of the milk yields. (a) Complete the ANOVA table below. ANOVA Table Source df SS MS F Diet 40.6875 Cow 54.6875 Lactation Period 147.1875 Error Total 247.4375 (14) (b) Are the the diet effects on milk yield significantly different from zero? Use the 0.05 level of significance. (6)