Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Draw the outcome of the following
![### Tertiary Butyl Bromide Reaction with Potassium tert-Butoxide
The diagram represents a reaction between tertiary butyl bromide and potassium tert-butoxide in the presence of tert-butanol (tBuOH).
**Chemical Structures:**
- The structure on the left is **tertiary butyl bromide**. It features a central carbon atom bonded to three methyl groups (CH₃) and one bromine atom (Br).
- The structure on the right represents **potassium tert-butoxide**. It consists of a tert-butyl group attached to an oxygen atom bearing a negative charge, which is balanced by a potassium ion (K⁺).
**Reaction Overview:**
- The arrow indicates the direction of the reaction under the conditions shown.
- The reaction takes place in a **tert-butanol** (tBuOH) solvent.
**General Equation:**
\[ \text{(CH₃)₃C-Br} + \text{KO-tBu} \xrightarrow{\text{tBuOH}} \text{Product(s)} \]
This type of reaction is typically an elimination reaction where the base (KO-tBu) removes a proton, leading to the formation of an alkene as the product.
**Key Concepts:**
- **Elimination Reaction:** This is likely an E2 mechanism due to the strong base and hindered substrate, resulting in the elimination of HBr and formation of isobutylene.
- **Solvent Role:** tBuOH acts as a solvent, stabilizing the intermediate species.
Understanding this reaction illustrates key concepts in nucleophilic substitution and elimination mechanisms, often explored in organic chemistry courses.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8cc4da3d-b98a-4b59-8ad6-754b41d863df%2F3ad7b6ce-8855-4de8-9cd3-538ff2b2c80a%2Fay1yd1o_processed.png&w=3840&q=75)
Transcribed Image Text:### Tertiary Butyl Bromide Reaction with Potassium tert-Butoxide
The diagram represents a reaction between tertiary butyl bromide and potassium tert-butoxide in the presence of tert-butanol (tBuOH).
**Chemical Structures:**
- The structure on the left is **tertiary butyl bromide**. It features a central carbon atom bonded to three methyl groups (CH₃) and one bromine atom (Br).
- The structure on the right represents **potassium tert-butoxide**. It consists of a tert-butyl group attached to an oxygen atom bearing a negative charge, which is balanced by a potassium ion (K⁺).
**Reaction Overview:**
- The arrow indicates the direction of the reaction under the conditions shown.
- The reaction takes place in a **tert-butanol** (tBuOH) solvent.
**General Equation:**
\[ \text{(CH₃)₃C-Br} + \text{KO-tBu} \xrightarrow{\text{tBuOH}} \text{Product(s)} \]
This type of reaction is typically an elimination reaction where the base (KO-tBu) removes a proton, leading to the formation of an alkene as the product.
**Key Concepts:**
- **Elimination Reaction:** This is likely an E2 mechanism due to the strong base and hindered substrate, resulting in the elimination of HBr and formation of isobutylene.
- **Solvent Role:** tBuOH acts as a solvent, stabilizing the intermediate species.
Understanding this reaction illustrates key concepts in nucleophilic substitution and elimination mechanisms, often explored in organic chemistry courses.
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