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OH NH₂ å 1. bl NH₂ 2. H₂O 1.1 eq 2. H₂O/ HCI (excess) -NH₂

OH NH₂ å 1. bl NH₂ 2. H₂O 1.1 eq 2. H₂O/ HCI (excess) -NH₂

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2c and 2d

**Concept Questions** **Predict the Product.** Provide the stable organic product(s) for the reactions below: 1. The first reaction involves a cyclic anhydride and ethylamine: - **Reactants:** - Cyclic anhydride - 1 equivalent of ethylamine - Second step: water/hydrochloric acid (H₂O/HCl) 2. The second reaction involves an acyl chloride and cyclopentanol: - **Reactants:** - Acyl chloride - Cyclopentanol in the presence of pyridine 3. The third reaction involves 2-aminophenol and an excess of acetic anhydride: - **Reactants:** - 2-aminophenol - Excess acetic anhydride - Second step: water (H₂O) 4. The fourth reaction involves a cyclic dianhydride and a diamine: - **Reactants:** - Cyclic dianhydride - 1 equivalent of 1,2-diaminocyclopentane - Second step: water/hydrochloric acid (H₂O/HCl) **Explanation of Reactions:** 1. In the first reaction, the ethylamine reacts with the anhydride to form an intermediate amide, which upon treatment with water and HCl, results in a stable carboxylic acid amide product. 2. In the second reaction, the acyl chloride reacts with cyclopentanol in the presence of pyridine, leading to the formation of an ester as the stable product. 3. In the third reaction, the 2-aminophenol reacts with the excess acetic anhydride, leading to acetylation on both the amino and hydroxyl groups. Upon hydrolysis, the stable product is a diacetylated derivative of the original compound. 4. In the final reaction, the 1,2-diaminocyclopentane reacts with the cyclic dianhydride to first form a cyclic imide, and upon treatment with water and HCl, results in a stable cyclic amide or imide product. Each of these reactions illustrates classic organic chemistry transformations involving amides, esters, and anhydrides.
Transcribed Image Text:**Concept Questions** **Predict the Product.** Provide the stable organic product(s) for the reactions below: 1. The first reaction involves a cyclic anhydride and ethylamine: - **Reactants:** - Cyclic anhydride - 1 equivalent of ethylamine - Second step: water/hydrochloric acid (H₂O/HCl) 2. The second reaction involves an acyl chloride and cyclopentanol: - **Reactants:** - Acyl chloride - Cyclopentanol in the presence of pyridine 3. The third reaction involves 2-aminophenol and an excess of acetic anhydride: - **Reactants:** - 2-aminophenol - Excess acetic anhydride - Second step: water (H₂O) 4. The fourth reaction involves a cyclic dianhydride and a diamine: - **Reactants:** - Cyclic dianhydride - 1 equivalent of 1,2-diaminocyclopentane - Second step: water/hydrochloric acid (H₂O/HCl) **Explanation of Reactions:** 1. In the first reaction, the ethylamine reacts with the anhydride to form an intermediate amide, which upon treatment with water and HCl, results in a stable carboxylic acid amide product. 2. In the second reaction, the acyl chloride reacts with cyclopentanol in the presence of pyridine, leading to the formation of an ester as the stable product. 3. In the third reaction, the 2-aminophenol reacts with the excess acetic anhydride, leading to acetylation on both the amino and hydroxyl groups. Upon hydrolysis, the stable product is a diacetylated derivative of the original compound. 4. In the final reaction, the 1,2-diaminocyclopentane reacts with the cyclic dianhydride to first form a cyclic imide, and upon treatment with water and HCl, results in a stable cyclic amide or imide product. Each of these reactions illustrates classic organic chemistry transformations involving amides, esters, and anhydrides.
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