offspring with Given the cross AaBbCc x Aabbcc, what is the probability of obtaining the genotype aabbCc? an

Human Anatomy & Physiology (11th Edition)
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Chapter1: The Human Body: An Orientation
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**Genetic Probability Calculation**

**Problem Statement:**

Given the genetic cross AaBbCc x Aabbcc, what is the probability of obtaining an offspring with the genotype aabbCc?

This problem involves understanding the inheritance patterns of three pairs of alleles (A/a, B/b, C/c) and calculating the probability of their combination in the offspring. To find this probability, you would break the problem into parts, calculating the probability for each gene independently, and then multiply the results together.

**Steps to Calculate:**

1. **Gene A/a:**
   - Probability of aa: The first parent (Aa) can pass on "a" with a probability of 1/2. The second parent (Aa) can also pass on "a" with a probability of 1/2.
   - Overall probability for aa: 1/2 * 1/2 = 1/4

2. **Gene B/b:**
   - Probability of bb: The first parent (Bb) can pass on "b" with a probability of 1/2. The second parent (bb) will always pass on "b", with a probability of 1.
   - Overall probability for bb: 1/2 * 1 = 1/2

3. **Gene C/c:**
   - Probability of Cc: The first parent (Cc) can pass on "C" with a probability of 1/2, and "c" with a probability of 1/2. The second parent (cc) will always pass on "c", with a probability of 1.
   - Overall probability for Cc: (1/2 from first parent) * (1 from second parent) + (1/2 from first parent) * (0 from second parent) = 1/2

**Combining Probabilities:**
- Transform understanding into a product of probabilities.
- Total probability for aabbCc: 1/4 (for aa) * 1/2 (for bb) * 1/2 (for Cc) = 1/16

Therefore, the probability of obtaining an offspring with the genotype aabbCc is 1/16.
Transcribed Image Text:**Genetic Probability Calculation** **Problem Statement:** Given the genetic cross AaBbCc x Aabbcc, what is the probability of obtaining an offspring with the genotype aabbCc? This problem involves understanding the inheritance patterns of three pairs of alleles (A/a, B/b, C/c) and calculating the probability of their combination in the offspring. To find this probability, you would break the problem into parts, calculating the probability for each gene independently, and then multiply the results together. **Steps to Calculate:** 1. **Gene A/a:** - Probability of aa: The first parent (Aa) can pass on "a" with a probability of 1/2. The second parent (Aa) can also pass on "a" with a probability of 1/2. - Overall probability for aa: 1/2 * 1/2 = 1/4 2. **Gene B/b:** - Probability of bb: The first parent (Bb) can pass on "b" with a probability of 1/2. The second parent (bb) will always pass on "b", with a probability of 1. - Overall probability for bb: 1/2 * 1 = 1/2 3. **Gene C/c:** - Probability of Cc: The first parent (Cc) can pass on "C" with a probability of 1/2, and "c" with a probability of 1/2. The second parent (cc) will always pass on "c", with a probability of 1. - Overall probability for Cc: (1/2 from first parent) * (1 from second parent) + (1/2 from first parent) * (0 from second parent) = 1/2 **Combining Probabilities:** - Transform understanding into a product of probabilities. - Total probability for aabbCc: 1/4 (for aa) * 1/2 (for bb) * 1/2 (for Cc) = 1/16 Therefore, the probability of obtaining an offspring with the genotype aabbCc is 1/16.
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