A power plant has an overall efficiency of 40%. The plant generates 40 MW of electricity and uses coal from Utah (see the table below) as fuel.The Typical Heating Value of Some CoalCoal from County and State ofHigher Heating Value (Btu/lbm)Musselshell, Montana12,075Emroy, Utah13,560Pike, Kentucky15,040Cambria, Pennsylvania15,595Williamson, Illinois13,710McDowell, West Virginia15,600Determine how much coal must be burned (in lbm/h) to sustain the generation of 40 MW of electricity. lbm/h

Given Data P=40W Overall efficiency=40% Coal:Utah(heating value: 13,560 BTU/lbm)Heat input Q= P/efficiency Q= 40/(0.4) Q=100 MW Now, 1 MW = 3,412,142 BTU/hr So, Q= 341214200 BTU/hrCoal consumption rate = Q/(Heating value) = 341214200/13560 = 25163.29 lbm/hr

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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A power plant has an overall efficiency of 40%. The plant generates 40 MW of electricity and uses coal from Utah (see the table below) as fuel.

The Typical Heating Value of Some Coal

Coal from County and State of	Higher Heating Value (Btu/lbm)
Musselshell, Montana	12,075
Emroy, Utah	13,560
Pike, Kentucky	15,040
Cambria, Pennsylvania	15,595
Williamson, Illinois	13,710
McDowell, West Virginia	15,600

Determine how much coal must be burned (in lbm/h) to sustain the generation of 40 MW of electricity.

lbm/h

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