A doctor took a random sample of n6 patients to see how long they each spent in the waiting room. Shewants to construct a't interval for the mean waiting time with 99% confidence. The times in the sample wereroughly symmetric with a mean of8.5 minutes and a standard deviation of sT2.8 minutes.What critical value t* should she use?Choose 1 answer:At* = 4.773Bt* = 4.032Ct* = 3.707t* = 3.365%3Dt* = 2.015

The degrees of freedom is: df = n-1=6-1=5 Significance level (α) =0.01

of n = 6 patients to see how long they each spent in the waitir wants to construct a't interval for the mean waiting time with 99% confidence. The times in the roughly symmetric with a mean of = 8.5 minutes and a standard deviation of s, = 2.8 minu %3D %3D What critical value t* should she use? Choose 1 answer: A t* = 4.773

of n = 6 patients to see how long they each spent in the waitir wants to construct a't interval for the mean waiting time with 99% confidence. The times in the roughly symmetric with a mean of = 8.5 minutes and a standard deviation of s, = 2.8 minu %3D %3D What critical value t* should she use? Choose 1 answer: A t* = 4.773

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A study of the career paths of hotel general managers sent questionnaires to an SRS of 210 hotels belonging to major U.S. hotel chains. There were 95 responses. The average time these 95 general managers had spent with their current company was 11.96 years. Take it as known that the standard deviation of time with the company for all general managers is 1.7 years. Give your answers to at least 2 decimal places, and use at least 3 decimal places in your critical value. (a) Find the margin of error for an 85% confidence interval to estimate the mean time a general manager had spent with their current company: years (b) Find the margin of error for a 99% confidence interval to estimate the mean time a general manager had spent with their current company: years (C) In general, increasing the confidence level the margin of error (width) of the confidence interval. (Enter: "DECREASES", "DOES NOT CHANGE" or "INCREASES", without the quotes..)
The weight of male babies less than 2 months old in the United States is normally distributed with mean 12.1 poundsand standard deviation 5.3. how are they working the problem to get 0.8224?
adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches find the z- score of a man 65.6 inches tall. ( to 2 decimal places)
A sample of size 31 was gathered from high school seniors to estimate how many intended to attend the state university. It is known that the proportion of the population answering "yes" was 0.7. What are the mean and standard deviation, and standard error of the mean of this sample? mean = E(p) = %3D standard error = SD(p) (accurate to 3 decimal places)
The lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days. What percentage of pregnancies last fewer than 314 days? P(x < 314 days) = P(z<
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1515 and a standard deviation of 304. The local college includes a minimum score of 2336 in its admission requirements.What percentage of students from this school earn scores that satisfy the admission requirement?P(X > 2336) = %Enter your answer as a percent accurate to 1 decimal place (do not enter the "%" sign). Answers obtained using exact z-scores or z-scores rounded to 3 decimal places
Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the height of a man with a z-score of -1.3 (to 2 decimal places)
During the busy season, it is important for the shipping manager at ShipMundo to be able to estimate the time it takes the loading crew to load a truck. The shipping manager has found that she can model the load times using a normal distribution with a mean of 152 minutes and a standard deviation of 15 minutes. Use this table or the ALEKS calculator to find the percentage of load times between 116 minutes and 149 minutes according to the model. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).