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of [ $ Example 29 a If the determinant of 5-3 3 is equal to 21, what is the value of x?

of [ $ Example 29 a If the determinant of 5-3 3 is equal to 21, what is the value of x?

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Example 29 a b 5 -3 of [] is equal to 21, what is the value of x? 2 3 x -4 what is the value of x for which A-A? c Show that if A and B are both square matrices and A + B is defined, then A B + A¹ is defined. Example 30 Given that A= If the determinant of For the matrix A= = [2²5] ² and that. at B=[2₂3]. The determinant of 4-1 and the determinant of B=2. Show that the value ofis 6. 23 | Page
Transcribed Image Text:Example 29 a b 5 -3 of [] is equal to 21, what is the value of x? 2 3 x -4 what is the value of x for which A-A? c Show that if A and B are both square matrices and A + B is defined, then A B + A¹ is defined. Example 30 Given that A= If the determinant of For the matrix A= = [2²5] ² and that. at B=[2₂3]. The determinant of 4-1 and the determinant of B=2. Show that the value ofis 6. 23 | Page
7 The prices of small, medium and large dogs at a pet shop are to decrease by 2%, 5% and 8% respectively If current prices are in matrix format P = prices, then the new prices would be 0.02 A. M-P where M = 0.05 0.08 0.98 B. M-P where M = 0.95 0.08 C. MP where M= D. MP where M= E. MP where M = 0.02 0 0 0 0.05 0 0 If = 0 0.08 0.98 0 0 0 0.95 0 0 0 0 0 0.92 -0.02 0 0 -0.05 0 0 -0.08 A-28-31 and B= 6 , where s, m and / represent small, medium and large dog then the matrix AB = - 30 96 24 48 The element '24' in the matrix AB is correctly obtained by calculating A. 4x6+2x0 B. 4 x 3 +2×x 6 C. 3 x 4 + 12 x 1 D. 4 × 2 + 8×2 E. 8x3+1×0 20 | Page
Transcribed Image Text:7 The prices of small, medium and large dogs at a pet shop are to decrease by 2%, 5% and 8% respectively If current prices are in matrix format P = prices, then the new prices would be 0.02 A. M-P where M = 0.05 0.08 0.98 B. M-P where M = 0.95 0.08 C. MP where M= D. MP where M= E. MP where M = 0.02 0 0 0 0.05 0 0 If = 0 0.08 0.98 0 0 0 0.95 0 0 0 0 0 0.92 -0.02 0 0 -0.05 0 0 -0.08 A-28-31 and B= 6 , where s, m and / represent small, medium and large dog then the matrix AB = - 30 96 24 48 The element '24' in the matrix AB is correctly obtained by calculating A. 4x6+2x0 B. 4 x 3 +2×x 6 C. 3 x 4 + 12 x 1 D. 4 × 2 + 8×2 E. 8x3+1×0 20 | Page
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