Of 1005 adults in a certain country responding to a​ poll, 47% said they always or often read nutrition labels when grocery shopping. a. Find a​ 95% confidence interval for the population proportion of adults in the country who always or often read nutrition labels when grocery shopping. Assume the poll used a simple random sample​ (SRS). (In​ fact, it used random​ sampling, but a more complex method than​ SRS.)   b. What is the width of the​ 95% confidence​ interval?   c. Name a confidence level that would produce an interval wider than the​ 95% confidence interval. Explain why you think this interval would be wider than a​ 95% confidence interval.

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Given that            sample size, n=20 Here, we have to construct a​ 95% confidence interval…

Q: What set of factors would produce the narrowest confidence interval for estimating a poulation mean?…

A: Objective of this question is that, which option is the correct choice.

Q: Use the sample data and confidence level given below to complete parts  (c).   A research institute…

A: It is given that, the number of respondents said yes (x) is 587 and the sample size (n) is 912.  The…

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: A poll for a statewide election has a margin of error of 2.14 percentage points. How many voters…

A: From the provided information,Margin of error (E) = 0.0214Confidence level = 99%

Q: In the measurement of support for one party, the sample data were n = 1300 and p̂ = 0.21. Compute a…

A: Given data: n = 1300  p̂ = 0.21. Confidence level = 95 %

Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…

A: a.

Q: The internal auditing staff of a local manufacturing company performs a sample audit each quarter to…

A:

Q: A poll reported 38% support for a statewide election with a margin of error of 1.36 percentage…

A: Proportion of voters who supports for a statewide election Margin of error Confidence level

Q: UCLA would like to conduct a study to estimate the proportion of all UCLA students attending…

A: The value of margin of error is, Critical values: Using the z-table, the critical value at 98%…

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: From the information out of 20 randomly selected presidents 8 are  taller than their opponents.

Q: 99% confidence interval for the proportion of the high school students who have been cyberbullied,…

A: Given that Sample size n = 14795 Number of high school students who have cyberbullied, X = 2219 The…

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: Refer to the data set of 2020 randomly selected presidents given below. Treat the data as a sample…

A: From the provided data set, it is clear that out of 20, 10 presidents were taller than their…

Q: A poll reported 60% support for a statewide election with a margin of error of 3.35  percentage…

A: The question is about sample size estimationGiven :Proportion of voters who supports for a statewide…

Q: Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and…

A: Out of the given sample of size, n = 20 the number of presidents whose heights were more than their…

Q: A poll asked whether states should be allowed to conduct random drug tests on elected officials. Of…

A:

Q: A poll asked whether states should be allowed to conduct random drug tests on elected officials. Of…

A: n = 21410 p^ = 0.72 99% ci for p

Q: 3469 adults aged 57 through 85​ years, it was found that 85.6​% of them used at least one…

A: It is given that sample size (n) is 3,469 and p hat value is 0.856.

Q: Refer to the accompanying data set of 20 randomly selected presidents. Treat the data as a sample…

A: The provided information is as follows:The sample size for each sample is .The level of confidence…

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

A:

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: Insurance companies are interested in knowing the popul drivers who always buckle up before riding…

A: Given data,No of people surveyed n=387who claims to buckle up is x=311Construct a 93 % CI?

Q: In a random sample of 184 college students, 97 had part-time jobs. Find the margin of error for the…

A: Given : Sample Size, n = 184 Number of successes, x = 97 confidence level,c=0.99

Q: Eleven students were randomly selected from a population of 1000 students. The sampling method was…

A: Let X represents English and Y represents Math  So mean of X, X bar = summation Xi /n =…

Q: f 260 employees selected randomly from one company, 18.46% of them commute by carpooling. Construct…

A: Given data, n=260 p=18.46% =0.1846 z-value at 98% confidence is Zc=2.326

Q: What is the best estimate for the standard error of the sampling

A: Given data,Tota no of students n=14795Who said yes for cyberbullied is x=2219Point estimate is…

Q: Find the sample size, n, needed to estimate the percentage of adults who have consulted fortune…

A: Obtain the sample size of a preliminary estimate for p is 0.14.   The formula of sample size is,…

Q: A polling firm called 1,000 likely voters to ask about their political preferences. Of those polled,…

A:

Q: A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and…

A: Confidence Rate = 95 Value Level = Î ± = (100-95)% = 0.05 Degrees of freedom = n-1 = 4 -1 = 3 Value…

Q: The Highway Safety Department wants to study the driving habits of individuals. A sample of 81 cars…

A: Given information Sample size (n) = 81 Sample mean x̅ = 67 mph Standard deviation (s) = 9 mph…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Q: An advertising agency wants to estimate the response rate for a new flyer. The agency sent the flyer…

A: sample size(n)=100No. of people received orders(x)=12

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.