Octane (C3H₁3) has a vapor pressure of 14.3 torr and a density of 0.703 g/mL. Benzene (C6H6) has a vapor pressure of 105.0 torr and a density of 0.876 g/mL. Assuming a mixture of the two behaved ideally and followed Raoult's Law, what would you predict to be the vapor pressure (in torr) of a solution containing 655 mL of octane and 465 mL of benzene?

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3:48 PM Mon Feb 6
Question 13 of 16
Octane (C3H18) has a vapor pressure of 14.3
torr and a density of 0.703 g/mL. Benzene
(C6H6) has a vapor pressure of 105.0 torr
and a density of 0.876 g/mL. Assuming a
mixture of the two behaved ideally and
followed Raoult's Law, what would you
predict to be the vapor pressure (in torr) of a
solution containing 655 mL of octane and
465 mL of benzene?
Tap here or pull up for additional resources
Transcribed Image Text:3:48 PM Mon Feb 6 Question 13 of 16 Octane (C3H18) has a vapor pressure of 14.3 torr and a density of 0.703 g/mL. Benzene (C6H6) has a vapor pressure of 105.0 torr and a density of 0.876 g/mL. Assuming a mixture of the two behaved ideally and followed Raoult's Law, what would you predict to be the vapor pressure (in torr) of a solution containing 655 mL of octane and 465 mL of benzene? Tap here or pull up for additional resources
Expert Solution
Step 1

Given:

The density and vapor pressure of octane are 0.703 g/mL and 14.3 torr respectively.

The density and vapor pressure of benzene are 0.876 g/mL and 105.0 torr respectively.

We have to calculate the vapor pressure of the solution containing 655 mL of octane and 465 mL of benzene.

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