Table 3.2odi ensiminimiCVEWLE-FSubstituent, Xbx stl-H lliw sadi sah asupstotoutieng Isixs-0.2od 24swin modis -0.2-0.5-0.511-CN-CI-Br1015Energy differences (AG) for equilibration of monosubstituted clcyclohexanes, C6H₁Xzadobadiam mord inprobibaabruogmos.sondy the 101-gur sel-OCH3-OH-COOH-CH3 CH#-CH=CH₂-CH₂CH3-CH(CH3)2AG (equatorial-axial) moc(kcal mol-1)-C6H5-C(CH3)3-C=CHDimethylcycloban-0.5goils, bars in cafH H-0.6-1.0-1.4-1.7-1.7-1.8 T-2.1-2.9-5.4EnergyvodeJoy wibor bfolavalvulad(Less stable conformations:half-chair, boat, twist-boat)H+AGⓇ314H-Xat E sugia For each of the following equilibria, say which side of the equilibrium is favored and by howmuch energy (see Table 3.2).HHد محمدBrCH3HOHH-HBrمدHOH

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Answered: -OCH3 -OH -COOH -CH3 -CH=CH₂ -CH₂CH3…

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Chemistry

-OCH3 -OH -COOH -CH3 -CH=CH₂ -CH₂CH3 -CH(CH3)2 -C6H5 H -0.6 -1.0 -1.4 -1.7 -1.7 -1.8 -2.1 -2.9 Energy X H + AGⓇ H -X

Chemistry

10th Edition

ISBN:9781305957404

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Table 3.2
odi ensiminimi
CVEWLE
-F
Substituent, X
bx stl
-H lliw sadi sah asupsto
toutieng Isixs
-0.2
od 24swin modis -0.2
-0.5
-0.5
11
-CN
-CI
-Br
1015
Energy differences (AG) for equilibration of monosubstituted cl
cyclohexanes, C6H₁X
zadobadiam mord inprobib
a
abruogmos.sondy the 101-gur sel
-OCH3
-OH
-COOH
-CH3 CH#
-CH=CH₂
-CH₂CH3
-CH(CH3)2
AG (equatorial-axial) moc
(kcal mol-1)
-C6H5
-C(CH3)3
-C=CHDimethylcycloban-0.5
goils, bars in caf
H H
-0.6
-1.0
-1.4
-1.7
-1.7
-1.8 T
-2.1
-2.9
-5.4
Energy
vode
Joy wibor b
folavalvulad
(Less stable conformations:
half-chair, boat, twist-boat)
H
+
AGⓇ
314
H
-X
at E sugia

For each of the following equilibria, say which side of the equilibrium is favored and by how
much energy (see Table 3.2).
H
H
د محمد
Br
CH3
H
OH
H
-
H
Br
مد
H
OH

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