**Title: Understanding Reactivity in Anionic Polymerization****Question:**Circle the compound that would be most reactive towards anionic polymerization and why?**Given Compounds:**1. **Compound 1:** - Structure: An alkene with a methoxy group: \( \text{H}_2\text{C}= \text{CH}-\text{OCH}_3 \)2. **Compound 2:** - Structure: An alkene with a cyano group: \( \text{H}_2\text{C}= \text{CH}-\text{CN} \)3. **Compound 3:** - Structure: An alkene: \( \text{H}_2\text{C}= \text{CH}_2 \)4. **Compound 4:** - Structure: An alkene with an amino group: \( \text{H}_2\text{C}= \text{CH}-\text{NH}_2 \)5. **Compound 5:** - Structure: An alkene with an ester group: \( \text{H}_2\text{C}= \text{CH}-\text{O}-\text{C}(= \text{O})-\text{CH}_3 \)**Explanation:**Anionic polymerization is a type of chain-growth polymerization initiated by anions. The reactivity of a compound towards anionic polymerization generally depends on the ability of the substituent group to stabilize the negative charge on the growing chain end.Among the given compounds, an ester group \( ( \text{O}-\text{C}(= \text{O})-\text{CH}_3 ) \) is strongly electron-withdrawing and has strong resonance stabilization of the negative charge. As a result, the compound with the ester group is the most reactive towards anionic polymerization.Therefore, the most reactive compound is:\[ \text{H}_2\text{C}= \text{CH}-\text{O}-\text{C}(= \text{O})-\text{CH}_3 \]This compound should be circled due to its high reactivity.

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Answered: OCH 3 CN NH₂ O

Science

Chemistry

OCH 3 CN NH₂ O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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