Obtain the moles of substance in the following. a. 3.04 g C mol b. 7.73 g Cl2 mol c. 72 g C4 H10 mol d. 75.8 g Al2 (CO3)3 mol

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A: given :-  molecular formula :  Al2O3  Al(NO3)3  To be calculated :-  molar mass of given compounds

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A: Welcome to bartleby! Actual yield = 43.7 g  Theoretical yield = 56.0 g

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