### Comparing Color Distribution in Candy Bags: An Educational Study#### Problem Statement:Observing that the proportion of blue candies in his bowl appeared to be less than that of the other colors, a student decided to compare the color distribution in randomly chosen bags of the candy to the theoretical distribution reported by the candy company's consumer affairs. For his study, the student bought three bags of the colored candies from local stores and counted the number of each color. The average number of each color in the three bags (rounded to the nearest integer) was distributed as shown to the right. Use this data to complete parts (a) through (c).#### Data Summary:| Color | Frequency ||---------|-----------|| Brown | 157 || Yellow | 112 || Red | 104 || Orange | 56 || Green | 43 || Blue | 43 |#### Calculation:1. **Obtain a relative-frequency distribution.** To calculate the relative frequency for each color, use the following formula: \[ \text{Relative Frequency} = \frac{\text{Frequency}}{\text{Total Number of Candies}} \] First, calculate the total number of candies: \[ 157 + 112 + 104 + 56 + 43 + 43 = 515 \] Then, calculate the relative frequency for each color: - Brown: \[ \frac{157}{515} \approx 0.3058 \] - Yellow: \[ \frac{112}{515} \approx 0.2175 \] - Red: \[ \frac{104}{515} \approx 0.2029 \] - Orange: \[ \frac{56}{515} \approx 0.1087 \] - Green: \[ \frac{43}{515} \approx 0.0835 \] - Blue: \[ \frac{43}{515} \approx 0.0835 \]#### Detailed Explanation:- The column “Color” lists the different colors of the candies.- The column “Frequency” shows the average number of each color candy in the bags.-

The following information has been provided: Color Frequency Brown 157 Yellow 112 Red 104…

Answered: Observing that the proportion of blue…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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During the first 13 weeks of the television season, the Saturday evening 8 p.m. to 9 p.m. audience proportions were recorded as ABC 31%, CBS 26%, NBC 27%, and independents 16%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 97 homes, CBS 68 homes, NBC 91 homes, and independents 44 homes. Test with a = 0.05 to determine whether the viewing audience proportions changed. State the null and alternative hypotheses. Ho: PABC + 0.31, PCBS H = 0.31, PCBS a: PABC O Ho: The proportions are not PABC H₂: PABC = 0.31, PCBS O Ho: PABC 0.31, PCBS + 0.26, PNBC = 0.26, PNBC + 0.27, PIND = 0.27, PIND Need Help? Read It = 0.31, PCBS = 0.26, PNBC 0.27, PIND = 0.16. = 0.16 = 0.27, PIND = 0.27, PIND = 0.16 = 0.26, PNBC = 0.26, PNBC H: The proportions are not PABC Ho: PABC = 0.31, PCBS = 0.26, PNBC + 0.31, PCBS = 0.27, PIND = 0.16 + 0.26, PNBC * 0.27, PIND * 0.16 Ha: PABC Find the value of the test statistic. (Round your answer to…
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