Objective 1-Understand ac power concepts, their relationshi 10.4 The load impedance in the circuit shown is shunted by a capacitor having a capacitive reac- tance of -52 N. Calculate: a) the rms phasors V and IL, b) the average power and magnetizing reactive power absorbed by the (39 + j26) N load impedance, c) the average power and magnetizing reactive power absorbed by the (1 + j4) N line impedance, d) the average power and magnetizing reactive power delivered by the source, and e) the magnetizing reactive power delivered by the shunting capacitor. 10 j4 N {39N 250 0º. V (rms) j26 N Source -Line- -Load Answer: (a) 252.20 /-4.54° V (rms), 5.38 /-38.23° A (rms); (b) 1129.09 W, 752.73 VAR;
Objective 1-Understand ac power concepts, their relationshi 10.4 The load impedance in the circuit shown is shunted by a capacitor having a capacitive reac- tance of -52 N. Calculate: a) the rms phasors V and IL, b) the average power and magnetizing reactive power absorbed by the (39 + j26) N load impedance, c) the average power and magnetizing reactive power absorbed by the (1 + j4) N line impedance, d) the average power and magnetizing reactive power delivered by the source, and e) the magnetizing reactive power delivered by the shunting capacitor. 10 j4 N {39N 250 0º. V (rms) j26 N Source -Line- -Load Answer: (a) 252.20 /-4.54° V (rms), 5.38 /-38.23° A (rms); (b) 1129.09 W, 752.73 VAR;
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:VASSESSMENT PROBLEMS
Objective 1-Understand ac power concepts, their relationships to one another, and how to calculate them in a circuit
10.4 The load impedance in the circuit shown is
(c) 23.52 W, 94.09 VAR;
shunted by a capacitor having a capacitive reac-
tance of – 52 N. Calculate:
(d) 1152.62 W, -376.36 VAR;
(e) 1223.18 VAR.
a) the rms phasors Vị and I4.
b) the average power and magnetizing reactive
power absorbed by the (39 + j26) N load
impedance,
10.5 The rms voltage at the terminals of a load is
250 V. The load is absorbing an average power
of 40 kW and delivering a magnetizing reactive
power of 30 KVAR. Derive two equivalent
impedance models of the load.
c) the average power and magnetizing reactive
power absorbed by the (1 + j4) N line
impedance,
d) the average power and magnetizing reactive
power delivered by the source, and
e) the magnetizing reactive power delivered by
the shunting capacitor.
Answer: 10 in series with 0.75 N of capacitive
reactance; 1.5625 N in parallel with 2.083 N
of capacitive reactance.
10.6 Find the phasor voltage V, (rms) in the circuit
shown if loads L1 and L2 are absorbing 15 kVA
at 0.6 pf lagging and 6 kVA at 0.8 pf leading,
respectively. Express V, in polar form.
10
j4 N
39 0
250 0º
V (rms)
jl N
j26 N
+
Source
- Line
Load
V,
200 20 V (rms) L1
L2
Answer: (a) 252.20 /-4.54° V (rms),
5.38 /-38.23° A (rms);
(b) 1129.09 W, 752.73 VAR;
Answer: 251.64 /15.91° V.
NOTE: Also try Chapter Problems 10.20, 10.28, and 10.30.
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