Obi-wan Kenobi has grown bored during his retirement on Tatooine and hasdecided to start Force-throwing womp rats at Jawas for fun. Womp rats have acharacteristic diameter of about 2 m according to Luke Skywalker, who enjoysshooting them from his T-16. To practice, Obi-wan sets up a Jawa-shaped posterto practice inside his hut and throws 25 cm diameter womp rat models at it. If areal womp rat thrown at 1.5 m/s is fatal to a Jawa, what is the maximum velocityObi-wan should use when throwing his model womp rat at his practice target?Conditions inside his air-filtered hut where he practices vs. the desert air wherehe will throw real womp rats are shown below.Air Inside HutDesert AirHair hutkg1.65E-5kgHair desert = 1.9E- 5%3Dm -Sm – SkgkgPair hut= 1.05m-Pair desert=1.21m

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Description: Obi-wan Kenobi has grown bored during his retirement on Tatooine and hasdecided to start Force-throwing womp rats at Jawas for fun. Womp rats have acharacteristic diameter of about 2 m according to Luke Skywalker, who enjoysshooting them from his T-

Answered: Obi-wan Kenobi has grown bored during…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Obi-wan Kenobi has grown bored during his retirement on Tatooine and has
decided to start Force-throwing womp rats at Jawas for fun. Womp rats have a
characteristic diameter of about 2 m according to Luke Skywalker, who enjoys
shooting them from his T-16. To practice, Obi-wan sets up a Jawa-shaped poster
to practice inside his hut and throws 25 cm diameter womp rat models at it. If a
real womp rat thrown at 1.5 m/s is fatal to a Jawa, what is the maximum velocity
Obi-wan should use when throwing his model womp rat at his practice target?
Conditions inside his air-filtered hut where he practices vs. the desert air where
he will throw real womp rats are shown below.
Air Inside Hut
Desert Air
Hair hut
kg
1.65E-5
kg
Hair desert = 1.9E- 5
%3D
m -S
m – S
kg
kg
Pair hut= 1.05
m-
Pair desert=1.21
m

Expert Solution

Step 1

Given that,

$R e a l d i a m e t e r o f w o m p r a t, D = 2 m, M o d e l d i a m e t e r o f w o m p r a t, d = 25 c m, V e l o c i t y o f r e a l w o m p r a t, V = 1.5 m / s e c, V i s \cos i t y o f a i r i n s i d e h u t, μ_{a i r, h u t} = 1.65 \times 10^{- 5} \frac{k g}{m \cdot s} D e n s i t y o f a i r i n s i d e h u t, ρ_{a i r, h u t} = 1.05 \frac{k g}{m^{3}} V i s \cos i t y o f D e s e r t a i r, μ_{a i r, d e s e r t} = 1.9 \times 10^{- 5} \frac{k g}{m \cdot s} D e n s i t y o f D e s e r t a i r, ρ_{a i r, d e s e r t} = 1.21 \frac{k g}{m^{3}}$

The model is practiced in the Air Inside Hut while the actual practice is to be done in Desert Air.

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