Obesity as % of the adult population 20 30
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You’ve come across research explaining the recent credit bubble by obesity. The research provided a strong
Critically evaluate the research findings and point out any potential problems with the methodology.
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- Population Genetics In the study of population genetics, an important measure of inbreeding is the proportion of homozygous genotypesthat is, instances in which the two alleles carried at a particular site on an individuals chromosomes are both the same. For population in which blood-related individual mate, them is a higher than expected frequency of homozygous individuals. Examples of such populations include endangered or rare species, selectively bred breeds, and isolated populations. in general. the frequency of homozygous children from mating of blood-related parents is greater than that for children from unrelated parents Measured over a large number of generations, the proportion of heterozygous genotypesthat is, nonhomozygous genotypeschanges by a constant factor 1 from generation to generation. The factor 1 is a number between 0 and 1. If 1=0.75, for example then the proportion of heterozygous individuals in the population decreases by 25 in each generation In this case, after 10 generations, the proportion of heterozygous individuals in the population decreases by 94.37, since 0.7510=0.0563, or 5.63. In other words, 94.37 of the population is homozygous. For specific types of matings, the proportion of heterozygous genotypes can be related to that of previous generations and is found from an equation. For mating between siblings 1 can be determined as the largest value of for which 2=12+14. This equation comes from carefully accounting for the genotypes for the present generation the 2 term in terms of those previous two generations represented by for the parents generation and by the constant term of the grandparents generation. a Find both solutions to the quadratic equation above and identify which is 1 use a horizontal span of 1 to 1 in this exercise and the following exercise. b After 5 generations, what proportion of the population will be homozygous? c After 20 generations, what proportion of the population will be homozygous?Score GPA Hours Absences Gender78 3.15 3.0 4 Female75 2.71 4.0 1 Female79 3.57 3.5 2 Male85 3.26 6.5 0 Female85 3.75 2.0 0 Female84 3.20 4.5 3 Female85 3.16 5.0 3 Male80 3.35 1.5 0 Female74 2.75 3.5 6 Male81 3.04 6.5 1 Male76 2.53 3.0 0 Female85 2.92 6.0 1 MaleA survey was conducted that asked 1018 people how many books they had read in the past year. Results indicated that x = 13.9 books and s = 16.6 books. Construct a 99% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. ..... Construct a 99% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) O A. If repeated samples are taken, 99% of them will have a sample mean between and B. There is a 99% probability that the true mean number of books read is between and O C. There is 99% confidence that the population mean number of books read is between ar
- Median Household Income ($) % of population over 25 with BA degree and higher 100,929 42.1 71,348 20.5 59,961 25.0 69,588 21.1 108,689 39.4 90,996 32.1 63,284 19.5 53,746 27.5 58,528 13.4 66,834 15.2 63,647 12.5 49,757 16.2 82,439 29.9 60,980 13.5 136,032 54.8 55,057 22.5 59,460 13.0 74,320 23.1 92,291 31.9 72,723 32.8 101,991 37.3 96,623 35.7…Listed in the accompanying table are weights (lb) of samples of the contents of cans of regular Coke and Diet Coke. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) to (c). Click the icon to view the data table of can weights. a. Use a 0.10 significance level to test the claim that the contents of cans of regular Coke have weights with a mean that is greater than the mean for Diet Coke. What are the null and alternative hypotheses? Assume that population 1 consists of regular Coke and population 2 consists of Diet Coke. A. Ho: H1 H2 H₁₁₂ OC. Ho HH2 H₁₁₂ The test statistic is 16.16. (Round to two decimal places as needed.) The P-value is 0.000. (Round to three decimal places as needed.) State the conclusion for the test. OB. Ho: H₁₂ H₁: H₁₂ OD. Ho: H1 H2 OA. Fail to reject the null hypothesis. There is sufficient evidence to support the…Year Change_Over_Five_Days Change_For_Entire_Year1 0.2 -0.22 0.2 -0.13 0.2 1.84 -0.4 1.25 -0.1 -0.36 0.2 -0.67 -0.1 0.88 -0.9 1.89 0.2 -0.710 0.1 -1.011 0.2 -1.0
- Fatalities Ln Safety Belt Rate 1071 3.951243719 1138 4.058717385 996 4.257030144 991 4.374498368 1038 4.365643155 1004 4.348986781 1154 4.382026635 1148 4.404277244 1207 4.417635062 1110 4.410371108 969 4.455509411 848 4.49980967 862 4.515245478 895 4.477336814 865 4.494238625 853 4.577798989 820 4.561218298 850 4.535820108 1083 4.521788577 948 4.531523646 953 4.519612298 856 4.525044142 create linear regression analysis through excelRenal Disease Suppose ten patients with advanced diabetic nephropathy (kidney complications of diabetes) were treated with captopril over an 8-week period. Urinary protein was measured before and after drug therapy, with results listed in the table below in both the raw and In scale. (Let population 1 be the measurement after treatment and population 2 be the measurement before treatment. Use after - before.) Changes in urinary protein after treatment with captopril Patient 1 2 3 4 5 6 7 8 9 10 Raw scale urinary protein (g/24 hr) Before USE SALT 25.7 17.1 15.9 10.5 8.1 7.8 5.7 5.5 5.0 4.8 After 10.2 5.6 5.7 3.5 6.4 0.8 6.2 4.6 2.1 2.8 In scale urinary protein (g/24 hr) Before 3.2465 2.8391 2.7663 2.3514 2.0919 2.0541 1.7405 1.7047 1.6094 1.5686 After 2.3224 1.7228 1.7405 1.2528 1.8563 -0.2231 1.8245 1.5261 0.7419 1.0296 (a) What is the appropriate statistical procedure to test whether mean urinary protein has changed over the 8-week period? (You may need to use the Distribution…Attack rate for influenza by age andtreatment group age QIV group Control group 3-4 3.78% 5.69% 5-8 1.70% 0.15% Suppose that 80% of 3–4-year-old children and 70% of 5–8-year-old children in a village are vaccinated with QIV vaccine. Also assume that children who are not vaccinated have twice the incidence of influenza as the control group in Table. What % of 3–4-year-old children in the village will get influenza? (Hint: Use the law of total probability. P(B)=P(B|A1) x P(A1) + P(B|A2) x P(A2) ) What % of 5–8-year-old children in the village will get influenza? (Hint: Use the law of total probability. P(B)=P(B|A1) x P(A1) + P(B|A2) x P(A2) )
- -In statistics, the percentage is the same or equivalent to the proportion (p). Percent means per 100. For example, if there are 1,000 residents in a town, and 60% are Democrats, then, on average, 60 out of each 100 are Democrats. You determine the total number of Democrats by converting the percentage to a proportion, .60, and multiplying .60 x 1,000, which equals 600. -To determine a percentage, we divide the part by the whole and multiply by 100. So, if 8 out of 234 seniors are reported to have tried Meth, we calculate the percentage: 8/234 0.0342 and multiply 0.0342 x 100= 3.42%. -Remember: when you multiply by 10, move the decimal point one place to the right3; when you multiply by 100, move the decimal point two places to the right, etc. Answer the questions that follow the Table below Adolescents at three drug treatment centers were surveyed. The questionnaire used consisted of 102 questions and was divided into four sections. The third section asked about past drug use. The…Player RBI HR AVG Salary (in millions) Prince Fielder 44 8 0.212 18.000 Jean Segura 64 20 0.320 2.600 Logan Forsythe 52 20 0.264 2.750 Chris Iannetta 24 7 0.210 4.550 Adam Jones 83 29 0.265 16.000 Curtis Granderson 59 30 0.237 16.000 Jason Heyward 49 7 0.230 21.667 Hanley Ramirez 111 30 0.286 22.750 David Ortiz 127 38 0.315 16.000 Matt Wieters 66 17 0.243 15.800 Colby Rasmus 54 15 0.206 15.800 Rajai Davis 48 12 0.249 5.950 Mike Trout 100 29 0.315 16.083 Troy Tulowitzki 79 24 0.256 20.000 Justin Smoak 34 14 0.217 3.900 Adrian Beltre 104 32 0.300 18.000 Matt Holliday 62 20 0.246 17.000 Hunter Pence 57 13 0.289 18.500 Brian McCann 58 20 0.242 17.000 J.D. Martinez 68 22 0.307 6.750 Ryan Braun 91 31 0.305 20.000 Mark Teixeira 44 15 0.204 23.125 Victor Martinez 86 27 0.289 18.000 Justin Upton 87 31 0.246 22.125 Carlos Gonzalez 100 25 0.298 17.454 Determine the correlation coefficient. (Round your answer to 4 decimal places.) Find the…Correlation 1. Eunice Consultancy took a random sample of the monthly office rents per square meter and the percentage of vacancy office space in 15 different cities. The results are shown in the table below. Monthly Rent Vacancy Rate X 01218609912201158912 4,000 7,500 5,300 6,200 8,000 5,000 9,000 3,400 4,400 5,100 8,000 9,000 9,900 8,800 9,000 a. Construct a scatter diagram. b. Calculate the coefficient of correlation using the Pearsons' Product-Moment Coefficient of Correlation and the Spearman's Rank-Order Coefficient of Correlation. c. Calculate the coefficient of correlation using the Spearman's Rank-Order Coefficient of Correlation. d. Interpret the results.