Oasis B is 9.0km due east of oasis A. Starting from oasis A, a camel walks 20 km in a direction15.0° south of east and thenwalks 34 km due north. If it is to then walk directly to B, (a) how far and (b) in what direction(relative to the positive x-axis within the range (-180°, 180°]) should it walk?Gruen data : Distance between A AND B'is d = 9,0 KmPlease Note:step Istep 2all the answeRs arecorrect,The vector diagram of displacement of camel is shown below.A From step 4 (b)Please explain (CindetailWhy y ou use the 270°Qnd - tan () insteodof ton" )Theunk jou!NRd2W-BECEIn above figure:Step 4d, = 20 km(а)d, = 34 kmThe distance travelled by the camel to reach the oasis B is:JBC + DCDB =Step 3(10.318 km ) +(28.823 km )*= 30.6 kmFrom geometrical property:(b) * Explaruthion, PleaseBC = AC – AB= d̟ cos15° - d= (20 km ) cos15° – 9.0 km 0 = 270° – ZCDB= 10.318 kmThe direction of displacement relative to positive x-axis isВС= 270°- tanDCDC = DE - CE10.318 km= 270° - tan= d, - d, sin 15°= 34 km - (20 km }sin15°28.823 km= 250.3°= 28.823 km= 250.3° – 360°= -109.7°

From the vector diagram, we can see that, resultant vector is in third quadrant. Resultant in below…

Oasis B is 4.0km due east of oasis A. Starting 15.0° south of east and then walks 34 km due north. If it is to then walk directly to B, (a) how far and (b) in what direction (relative to the positive x-axis within the range (-180°, 180°)) should it walk? step L Grven data : Distance between A AND B'is d = 9.0 Km step 2 Please Note: all the ausweRs are correct, The vector diagram of displacement of camel is shown below. * From step 4 (b) Please explain (in detail D Why you use the 270° Qard - tan() instevd E of tan" () R W- A B

Oasis B is 4.0km due east of oasis A. Starting 15.0° south of east and then walks 34 km due north. If it is to then walk directly to B, (a) how far and (b) in what direction (relative to the positive x-axis within the range (-180°, 180°)) should it walk? step L Grven data : Distance between A AND B'is d = 9.0 Km step 2 Please Note: all the ausweRs are correct, The vector diagram of displacement of camel is shown below. * From step 4 (b) Please explain (in detail D Why you use the 270° Qard - tan() instevd E of tan" () R W- A B

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Scalars and Vectors

Scalars and Vectors are the classification of physical quantities that are used to denote various terms in physics.

Question

Oasis B is 9.0km due east of oasis A. Starting from oasis A, a camel walks 20 km in a direction
15.0° south of east and then
walks 34 km due north. If it is to then walk directly to B, (a) how far and (b) in what direction
(relative to the positive x-axis within the range (-180°, 180°]) should it walk?
Gruen data : Distance between A AND B'is d = 9,0 Km
Please Note:
step I
step 2
all the answeRs are
correct,
The vector diagram of displacement of camel is shown below.
A From step 4 (b)
Please explain (Cindetail
Why y ou use the 270°
Qnd - tan () insteod
of ton" )
Theunk jou!
N
R
d2
W-
B
E
C
E
In above figure:
Step 4
d, = 20 km
(а)
d, = 34 km
The distance travelled by the camel to reach the oasis B is:
JBC + DC
DB =
Step 3
(10.318 km ) +(28.823 km )*
= 30.6 km
From geometrical property:
(b) * Explaruthion, Please
BC = AC – AB
= d̟ cos15° - d
= (20 km ) cos15° – 9.0 km 0 = 270° – ZCDB
= 10.318 km
The direction of displacement relative to positive x-axis is
ВС
= 270°- tan
DC
DC = DE - CE
10.318 km
= 270° - tan
= d, - d, sin 15°
= 34 km - (20 km }sin15°
28.823 km
= 250.3°
= 28.823 km
= 250.3° – 360°
= -109.7°

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