oads are: 0₁ 40° and 0₂ = 30° and the dimensions are a = 5 m, b = s to derive expressions for the internal resultant loadings, i.e., nor as well as bending moment (M) at the cross-section of the bear ssions must be valid for 0

Structural Analysis
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Chapter2: Loads On Structures
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100 N/m,
A simply supported beam ABCD is subjected to a linearly distributed load, with wo
two concentrated loads, one at C and the other at D, and a point moment at B as shown in Figure
4.1. The angles of the point loads are: 0₁ = 40° and 0₂ = 30° and the dimensions are a = = 5 m, b = 3
m and c = 2 m.
b) Use the method of sections to derive expressions for the internal resultant loadings, i.e., normal
(N) and shear (V) forces as well as bending moment (M) at the cross-section of the beam as
functions of x. The expressions must be valid for 0≤x≤a and a ≤x≤ b and b≤x≤c. Check
that your equations provide values at the midpoint of AB that are consistent with your results
in part a.
Wo
A
X
a
B
1
500 N
의
200 N·m
b
Figure 4.1. - Simply supported beam
0₂
2
300 N
Transcribed Image Text:100 N/m, A simply supported beam ABCD is subjected to a linearly distributed load, with wo two concentrated loads, one at C and the other at D, and a point moment at B as shown in Figure 4.1. The angles of the point loads are: 0₁ = 40° and 0₂ = 30° and the dimensions are a = = 5 m, b = 3 m and c = 2 m. b) Use the method of sections to derive expressions for the internal resultant loadings, i.e., normal (N) and shear (V) forces as well as bending moment (M) at the cross-section of the beam as functions of x. The expressions must be valid for 0≤x≤a and a ≤x≤ b and b≤x≤c. Check that your equations provide values at the midpoint of AB that are consistent with your results in part a. Wo A X a B 1 500 N 의 200 N·m b Figure 4.1. - Simply supported beam 0₂ 2 300 N
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