Please do SubSets Do: Graded Chapter 8 Problem SetStandard Deviation = 1.0.5000.2500.2500-3-2-1234-0.670.67The critical region is the area in the tails beyond each z-score vThe z-score boundaries for an alpha level a = 0.01 are:O z = 3.29 and z = -3.29O z = 1.96 and z = -1.96O z = 2.58 and z = -2.58Suppose that the calculated z statistic for a particular hypothesis test is 1.92 and the alpha is 0.01. This z statistic isv the critical region.Therefore, the researcherv reject the null hypothesis, and heconclude the alternative hypothesis is probably correct. Do: Graded Chapter 8 Problem Set3. Alpha level and the critical regionThe alpha level that a researcher sets at the beginning of the experiment is the level to which he wishes to limit the probability of making the error ofrejecting the null hypothesis when it is trueGlossarUse the following Distributions tool to identify the boundaries that separate the extreme samples from the samples that are more obviously consistentwith the null hypothesis. Assume the null hypothesis is nondirectional, meaning that the critical region is split across both tails of the distribution.The z-score boundaries at an alpha level a = .05 are:O z = 2.58 and z = -2.58O z = 1.96 and z = -1.96O z = 3.29 and z = -3.29To use the tool to identify the z-score boundaries, click on the icon with two orange lines, and slide the orange lines until the area in the critical regionequals the alpha level. Remember that the probability will need to be split between the two tails.To use the tool to help you evaluate the hypothesis, click on the icon with the purple line, place the two orange lines on the critical values, and thenplace the purple line on the z statistic.Standard Normal Distribution

The given information in this question The z score boundaries for an alpha level α =0.01 The critical value at α = 0.01 is 2.58 and -2.58 ( standard normal table of z ) given that z = 1.92 < 2.58 then the do not reject null hypothesis and the alternative hypothesis is probably correct The given information at α =0.05 the critical value is 1.96 and -1.96 by standard normal table of z