O y"'+ 4y' + 4y =(3+x) e-2x, when x = 0, y = 2, y'= 5 3 -2x -(1/₁³3 ²+ = -₁ ² 0 - ² O O O y = 2e general -2x -2x + 9xe + y=2e²x + 4xe 2x y=2e-2x = xe + [ - = x ² + 1/{ x² ) ² + -2x -2x y=2e - 3xe 3 - 1/₁²) 0² -2x applies). 1 -2x -2x -² + ( + x ² - - - - - - ²0
O y"'+ 4y' + 4y =(3+x) e-2x, when x = 0, y = 2, y'= 5 3 -2x -(1/₁³3 ²+ = -₁ ² 0 - ² O O O y = 2e general -2x -2x + 9xe + y=2e²x + 4xe 2x y=2e-2x = xe + [ - = x ² + 1/{ x² ) ² + -2x -2x y=2e - 3xe 3 - 1/₁²) 0² -2x applies). 1 -2x -2x -² + ( + x ² - - - - - - ²0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![Determine the general/particular solution (whichever applies):
y''+ 4y' + 4y = (3+x) e −2x, when x = 0, y = 2, y'=5
O
O
O
y = 2e
y = 2e
- 2x
y = 2e
2x
y=2e²+ 4xe +
-2x
+ 9xe
-2x
-2x
- xe
-2x
+
-2x
- 3xe +
1
1
3
3
3
'+
-
2
2 / +²7)
=+=+²) 0²
1
x²-21
3
-2x
2x
- 2x
-2x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57152b2f-3c94-426a-8f95-b1d84d1e9e7f%2F51844f25-390b-4bb8-99c6-2be91e374182%2Fchfuqec_processed.png&w=3840&q=75)
Transcribed Image Text:Determine the general/particular solution (whichever applies):
y''+ 4y' + 4y = (3+x) e −2x, when x = 0, y = 2, y'=5
O
O
O
y = 2e
y = 2e
- 2x
y = 2e
2x
y=2e²+ 4xe +
-2x
+ 9xe
-2x
-2x
- xe
-2x
+
-2x
- 3xe +
1
1
3
3
3
'+
-
2
2 / +²7)
=+=+²) 0²
1
x²-21
3
-2x
2x
- 2x
-2x
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