O »(x) = Given the differential equation y' = 8x + 4 y' and y (0) = 1 and its next few implicit derivatives y" = 8 + 4 y' y'' = 4 y" %3D Use the initial value "y(0) = 1" to find the value of "y'(0)", "y"(0)", and "y"(0)", then plug them into the Taylor Series Polynomial formula. 160 (A y(x) 0! 8 x' + 1! 40 x2 + ... 2! 3! B y(x) 0! 8. x! 8. x2 + x3 + 1! 2! 3! y(x) O! 12 x + 1! 12 x2 + 4 r3 + ... 3! - 2! 12 D y(x) x0 0! 54 x2 + ? x + ... | 1! 2! 3! E E y(x) O! 4 x! 12 x2 + 4 x3 + 3! - - 1! 2! y(x) = 24 x2 + 2! 96 -r3 +... F x° + 0! x'+ 1! 3! +

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