O Use the Bonferonni method for the tomato plant dataset of class notes and construct confidence intervals for all three irs, Hi-Hj, i +j, i,j = 1, 2, 3 with joint confidence of 94%. Using these make a decision as to which plants may have fferent average yields. ne following answers" have been proposed. O None of the three confidence intervals contain zero. Therefore, all three plants have, on average, significantly fferent yields. O All three confidence intervals contain zero. Therefore, all three plants have, on average, the same yield. O The confidence intervals for µ1 - 42 and u2 - 43 do not contain zero. The confidence interval for µj - 43 contains zero. nerefore, the result becomes a bit confusing to interpret. O The confidence intervals for u1 - 42 and µ - µ3 do not contain zero. The confidence interval for µ3 - 12 contains zero. herefore, u2 and µ3 may be equal, but µ1 differs from both 12 and 43.

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(6) Use the Bonferonni method for the tomato plant dataset of class notes and construct confidence intervals for all three
pairs, µi – Hj, i + j, i.j = 1,2, 3 with joint confidence of 94%. Using these make a decision as to which plants may have
different average yields.
The following "answers" have been proposed.
(a) None of the three confidence intervals contain zero. Therefore, all three plants have, on average, significantly
different yields.
(b) All three confidence intervals contain zero. Therefore, all three plants have, on average, the same yield.
(c) The confidence intervals for µ1 – 42 and µ2 – 43 do not contain zero. The confidence interval for uj – µ3 contains zero.
Therefore, the result becomes a bit confusing to interpret.
(d) The confidence intervals for µ1 – µ2 and µ1 – µ3 do not contain zero. The confidence interval for 43 – µ2 contains zero.
Therefore, µ2 and µ3 may be equal, but µ1 differs from both
(e) None of the above.
and
H2
H3.
The correct answer is
(a)
(b)
(c)
(d)
(e)
N/A
(Select One)
Transcribed Image Text:(6) Use the Bonferonni method for the tomato plant dataset of class notes and construct confidence intervals for all three pairs, µi – Hj, i + j, i.j = 1,2, 3 with joint confidence of 94%. Using these make a decision as to which plants may have different average yields. The following "answers" have been proposed. (a) None of the three confidence intervals contain zero. Therefore, all three plants have, on average, significantly different yields. (b) All three confidence intervals contain zero. Therefore, all three plants have, on average, the same yield. (c) The confidence intervals for µ1 – 42 and µ2 – 43 do not contain zero. The confidence interval for uj – µ3 contains zero. Therefore, the result becomes a bit confusing to interpret. (d) The confidence intervals for µ1 – µ2 and µ1 – µ3 do not contain zero. The confidence interval for 43 – µ2 contains zero. Therefore, µ2 and µ3 may be equal, but µ1 differs from both (e) None of the above. and H2 H3. The correct answer is (a) (b) (c) (d) (e) N/A (Select One)
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