O The system has no solution. -x + 2y = 6 The system has a unique solution: %3D x- 2y = 6 (-») - CD The system has infinitely many solutions They must satisfy the following equation >-0 The system has no solution. -x + 2y = 4 The system has a unique solution: X - 2y = -4 (x9) - CD The system has infinitely many solutions They must satisfy the following equation > - 0

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.7: Solving Systems Of Linear And Quadratic Equations
Problem 3GP
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### Unproctored Placement Assessment

#### Problem Description

Two systems of equations are given below. For each system, choose the best description of its solution. If applicable, give the solution.

#### System 1:
\[ 
- x + 2y = 6 
\]
\[ 
x - 2y = 6 
\]

Options:
- The system has no solution.
- The system has a unique solution: \((x, y) = \text{{input boxes}}\)
- The system has infinitely many solutions. They must satisfy the following equation: \(y = \text{{input box}}\)

#### System 2:
\[ 
- x + 2y = 4 
\]
\[ 
x - 2y = -4 
\]

Options:
- The system has no solution.
- The system has a unique solution: \((x, y) = \text{{input boxes}}\)
- The system has infinitely many solutions. They must satisfy the following equation: \(y = \text{{input box}}\)

---

To solve these systems, consider using methods such as substitution, elimination, or graphical analysis to determine the number of solutions and, if applicable, find the values of \(x\) and \(y\).

Buttons:
- **I Don’t Know**
- **Submit**
Transcribed Image Text:### Unproctored Placement Assessment #### Problem Description Two systems of equations are given below. For each system, choose the best description of its solution. If applicable, give the solution. #### System 1: \[ - x + 2y = 6 \] \[ x - 2y = 6 \] Options: - The system has no solution. - The system has a unique solution: \((x, y) = \text{{input boxes}}\) - The system has infinitely many solutions. They must satisfy the following equation: \(y = \text{{input box}}\) #### System 2: \[ - x + 2y = 4 \] \[ x - 2y = -4 \] Options: - The system has no solution. - The system has a unique solution: \((x, y) = \text{{input boxes}}\) - The system has infinitely many solutions. They must satisfy the following equation: \(y = \text{{input box}}\) --- To solve these systems, consider using methods such as substitution, elimination, or graphical analysis to determine the number of solutions and, if applicable, find the values of \(x\) and \(y\). Buttons: - **I Don’t Know** - **Submit**
**Unproctored Placement Assessment**

**Time Remaining:** 23:12:35

**Question 7**

Two systems of equations are given below. For each system, choose the best description of its solution. If applicable, give the solution.

---

1. **System of Equations:**

   \(-x + 2y = 6\)
   
   \(x - 2y = 6\)

   **Options:**

   - The system has no solution.
   - The system has a unique solution: \((x,y) = \boxed{\phantom{00}}\)
   - The system has infinitely many solutions. They must satisfy the following equation: \(y = \boxed{\phantom{00}}\)

---

2. **System of Equations:**

   \(-x + 2y = 4\)
   
   \(x - 2y = -4\)

   **Options:**

   - The system has no solution.
   - The system has a unique solution: \((x,y) = \boxed{\phantom{00}}\)
   - The system has infinitely many solutions. They must satisfy the following equation: \(y = \boxed{\phantom{00}}\)

---

**Controls:**

- [I Don't Know] [Submit]

© 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy | Accessibility
Transcribed Image Text:**Unproctored Placement Assessment** **Time Remaining:** 23:12:35 **Question 7** Two systems of equations are given below. For each system, choose the best description of its solution. If applicable, give the solution. --- 1. **System of Equations:** \(-x + 2y = 6\) \(x - 2y = 6\) **Options:** - The system has no solution. - The system has a unique solution: \((x,y) = \boxed{\phantom{00}}\) - The system has infinitely many solutions. They must satisfy the following equation: \(y = \boxed{\phantom{00}}\) --- 2. **System of Equations:** \(-x + 2y = 4\) \(x - 2y = -4\) **Options:** - The system has no solution. - The system has a unique solution: \((x,y) = \boxed{\phantom{00}}\) - The system has infinitely many solutions. They must satisfy the following equation: \(y = \boxed{\phantom{00}}\) --- **Controls:** - [I Don't Know] [Submit] © 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use | Privacy | Accessibility
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