O Macmillan Learning Experiment 1: For each test tube, calculate the concentration of H3O+ and the pH. You can use the dilution formula to determine the concentration of HCI M₁ × V₁ = M2 × V₂ where M₁ and V₁ are the molarity and volume of the first solution, respectively, and M2 and V2 are the molarity and volume of the second solution, respectively. Given that HCl is a strong acid, the H3O+ concentration is equal to the HCl concentration except at very low concentrations (test tubes 6 and 7), where the H₂O+ from the dissociation of water (1.00 x 10-7 M) becomes significant. Test tube 1 2 3 4 5 6 7 [HC1] (M) [H3O+] (M) pH

Chemistry
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Chapter1: Chemical Foundations
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O Macmillan Learning
Experiment 1: For each test tube, calculate the concentration of H3O+ and the pH. You can use the dilution formula to
determine the concentration of HCI
M₁ × V₁ = M2 × V₂
where M₁ and V₁ are the molarity and volume of the first solution, respectively, and M2 and V2 are the molarity and volume of
the second solution, respectively.
Given that HCl is a strong acid, the H3O+ concentration is equal to the HCl concentration except at very low concentrations
(test tubes 6 and 7), where the H₂O+ from the dissociation of water (1.00 x 10-7 M) becomes significant.
Test tube
1
2
3
4
5
6
7
[HC1] (M)
[H3O+] (M)
pH
Transcribed Image Text:O Macmillan Learning Experiment 1: For each test tube, calculate the concentration of H3O+ and the pH. You can use the dilution formula to determine the concentration of HCI M₁ × V₁ = M2 × V₂ where M₁ and V₁ are the molarity and volume of the first solution, respectively, and M2 and V2 are the molarity and volume of the second solution, respectively. Given that HCl is a strong acid, the H3O+ concentration is equal to the HCl concentration except at very low concentrations (test tubes 6 and 7), where the H₂O+ from the dissociation of water (1.00 x 10-7 M) becomes significant. Test tube 1 2 3 4 5 6 7 [HC1] (M) [H3O+] (M) pH
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