Formula shown is incorrect **Title: Understanding the Reaction between Alcohol and Tosyl Chloride with a Nucleophile****Objective:**Learn how to predict the main organic product formed in a reaction between an alcohol and tosyl chloride, followed by the introduction of a nucleophile.**Body:****Reaction Description:**The starting material for this reaction is an alcohol, specifically, propanol represented by the formula:\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \]**Reaction Steps:**1. **First Step: Reaction with Tosyl Chloride (TsCl) and Pyridine** - The alcohol reacts with tosyl chloride in the presence of pyridine. - This step transforms the alcohol into a tosylate, which is a better leaving group.2. **Second Step: Nucleophilic Substitution** - The tosylate product is then exposed to a nucleophile, specifically the cyanide ion (NC^-). - This step results in nucleophilic substitution, replacing the tosylate group with the nucleophile to produce a nitrile.**Expected Product:**The expected product after these reactions should be butyronitrile, represented by the formula:\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{CN} \]**Error Noted:**In the transcription, an incorrect product was suggested:\[ \text{CH}_3\text{CH}_2\text{CN} \] This product is missing a methylene group (CH2), and hence it does not align with the starting material propanol.**Conclusion:**Understanding the mechanism of this reaction helps in predicting the correct structures of organic compounds formed through sequential reactions involving activation of alcohols and subsequent nucleophilic substitution.

The given reaction can be explained as : In this reaction pyridine abstract H+ ion from alcohol group and make it good nucleophile which further attack on tosayl chloride (Ts-Cl ) group . Thus alcohol become good leaving group now and can show SN2 reaction easily with CN- group as shown below: