O Macmillan Learning A precipitation reaction occurs when 795 mL of 0.824 M Pb(NO3)2 reacts with 341 mL of 0.908 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 KI(aq) Pbl₂(s) + 2 KNO3(aq) Identify the limiting reactant. KNO3 Pb(NO3)2 KI РЫ2 Calculate the theoretical yield of Pbl, from the reaction. mass of Pbl₂: Incorrect Calculate the percent yield of Pbl, if 59.7 g of Pbl₂ are formed experimentally. percent yield of Pbl₂: Incorrect % g

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Chapter1: Chemical Foundations
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O Macmillan Learning
A precipitation reaction occurs when 795 mL of 0.824 M Pb(NO3)2 reacts with 341 mL of 0.908 M KI, as shown by the
following equation.
Pb(NO3)2(aq) + 2 KI(aq)
Pbl₂(s) + 2 KNO3(aq)
Identify the limiting reactant.
KNO3
Pb(NO3)2
KI
РЫ2
Calculate the theoretical yield of Pbl, from the reaction.
mass of Pbl₂:
Incorrect
Calculate the percent yield of Pbl, if 59.7 g of Pbl₂ are formed experimentally.
percent yield of Pbl₂:
Incorrect
%
g
Transcribed Image Text:O Macmillan Learning A precipitation reaction occurs when 795 mL of 0.824 M Pb(NO3)2 reacts with 341 mL of 0.908 M KI, as shown by the following equation. Pb(NO3)2(aq) + 2 KI(aq) Pbl₂(s) + 2 KNO3(aq) Identify the limiting reactant. KNO3 Pb(NO3)2 KI РЫ2 Calculate the theoretical yield of Pbl, from the reaction. mass of Pbl₂: Incorrect Calculate the percent yield of Pbl, if 59.7 g of Pbl₂ are formed experimentally. percent yield of Pbl₂: Incorrect % g
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