### Class Survey Analysis**Survey Overview:**A class survey in a large first-year college class asked students, "About how many hours do you study during a typical week?" The data collected revealed:- **Mean response of 463 students was** $ \bar{x} = 13.7 $ hours.- **Assumed normal distribution** of study time with a standard deviation $ \sigma = 7.4 $ hours.- **99% confidence interval** was calculated to be approximately 12.814 to 14.586 hours.**Outlier Identification:**There were actually 464 responses. One student reported studying 10,000 hours per week (clearly more than the number of hours in a year). This outlier was removed from initial calculations due to its implausibility.**New Calculation Without Outlier:**- With this outlier included, the recalculated mean is $ \bar{x} = 35.2 $ hours for all 464 students.- **New 99% confidence interval** requested for calculation using the same standard deviation: $ \sigma = 7.4 $.**Instructions for Calculation:**Input your answers to three decimal places for the new interval:- **Lower bound:**- **Upper bound:****Comparison and Analysis:**Evaluate how the inclusion of the outlier alters the statistical data:- The outlier had a huge impact on $ \bar{x} $, significantly narrowing the interval.- or- The outlier had a huge impact on $ \bar{x} $, significantly shifting the interval. **Transcription for Educational Website**---**Upper Bound:** [Input Box]**Compare the new interval with the one where the outlier had been removed. What is the effect of the outlier?**1. ○ The outlier had a huge impact on $\bar{x}$, which narrows the interval a lot.2. ○ The outlier had a huge impact on $\bar{x}$, which shifts the interval a lot.3. ○ The outlier had a huge impact on $\bar{x}$ and the margin of error, which both shifts and broadens the interval a lot.4. ○ The outlier had a huge impact on the margin of error, which broadens the interval a lot.**The message is clear: always look at your data because outliers can greatly change your result.**---**Note:** The National Survey of Student Engagement conducts an annual survey that includes hours spent preparing for class each week. The numbers in this exercise are based on the results of the 2015 survey. You can find survey results at [nsse.indiana.edu/html/findings.cfm](http://nsse.indiana.edu/html/findings.cfm).---### Diagrams/Graphs Explanation:- There are no diagrams or graphs included in the image provided.---This content can be utilized to educate students about the impact of outliers on statistical calculations and to emphasize the importance of analyzing data critically.

From the provided information,sample size (n) = 464Sample mean (x̄) = 35.2Population standard deviation (σ) = 7.4Confidence level = 99%The confidence level is 0.99.For critical value use the EXCEL command as, “= NORMSINV (probability)”Insert the values as, “= NORMSINV (0.995)”From the EXCEL output, the critical value is 2.576.The confidence interval can be obtained as:Thus, the required 99% confidence interval for the population mean is from 34.315 hours to 36.085 hours.comparison:The outlier had a huge impact on and the margin of error, which both shifts and broadens the interval a lot.lower bound = 34.315upper bound = 36.085The outlier had a huge impact on and the margin of error, which both shifts and broadens the interval a lot.